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krek1111 [17]
2 years ago
6

Provide the organometallic reagent that is needed to perform the transformation shown below. The reagent should be formatted as

LiR or BrMgR, where R is an alkyl group written as a Condensed Formula. Do not use subscripts.
Chemistry
1 answer:
Juliette [100K]2 years ago
4 0

The correct answer is   LiCH_{3}CH(CH_{3} )CH_{3} .

<h3>Organometallic reagent</h3>

Organometallic chemistry is the study of organometallic compounds, which are substances that contain at least one chemical bond between a carbon atom from an organic molecule and a metal. These substances include alkali, alkaline earth, and transition metals, as well as metalloids like boron, silicon, and selenium. In addition to links to organyl fragments or molecules, bonds to 'inorganic' carbon, such as those to carbon monoxide (metal carbonyls), cyanide, or carbide, are also typically regarded as organometallic. Although they are not strictly speaking organometallic compounds, some similar compounds, such as transition metal hydrides and metal phosphine complexes, are frequently included in discussions of such substances. The phrase "metalorganic compound," which is comparable but different, describes molecules that contain metals but do not have direct metal-carbon bonds but do have organic ligands.

Learn more about organometallic reagent here:

brainly.com/question/13299409

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C3H7-C(=O)-NH2 IUPAC NAME ?
Yuri [45]

Answer:

Amide

Explanation:

O=NH2 is the Amide group versus NH2, which is the amine group.

7 0
3 years ago
Read 2 more answers
Which type of reaction is indicated by a positive AH?
lianna [129]

Answer:

An endothermic reaction

Explanation:

A positive sign indicates that energy is absorbed. Hence it is an endothermic reaction.

A reversible reaction is indicated by a double arrow on the chemical equation.

A spontaneous is indicated by negative Gibbs Free Energy (G) value.

An exothermic reaction is indicated by a negative enthalpy change

5 0
3 years ago
What is the molarity of the Ca(OH)2 solution if 32.00 mL of Ca(OH)2 requires 16.08 mL of a 2.303 M solution for complete titrati
amm1812

Answer:

For this problem we just need to remember the equation and that the volume is always in liters: MaVa=MbVb

  Ma= 1.338 mol/L Va= 18.75 mL= 0.01875 L Mb= x Vb=24.73 mL= 0.02473 L

 

  So now we can plug into the equation and solve:

   1.338 mol/L * 0.01875 L= x mol/L * 0.02473 L

This is a two step process: stoichiometry and using the answer from the first part to plug and chug it into the Molariy equation.

  First step: setup the stoichiometry problem:

  3.1171 g Na2CO3 * (1 mol/106 g) * (2 mol HCl/ 1 mol Na2CO3)= mol HCl

 

  Second step: Molarity equation

  Molarity= moles HCl/ L   M= mol HCl/0.04027 L

For the third problem, you will just use the same equation as the first: MaVa= MbVb

  Ma=0.57 M   Va= x L   Mb= 0.875 M  Vb= 23.83 mL= 0.02383 L

  0.57 M * x L= 0.875 M * 0.02383 L

With this equation, we want to find the moles of NaOH by using the molarity equation first then because MaVa= MbVb, we know that the number of moles has to be equal.

   0.75 M= x mol/ 0.0227 L    mol NaOH = 0.75 M *0.0227 L         mol NaOH= 0.017025

  So next, we can set it to the mass of the acid using this equation: Molar Mass= mass/ moles

  Molar Mass= 3.6 g/ 0.017025 mol  

 And with that you will find the molar mass of HX, and even determine what X is.

Explanation:

hope I helped

8 0
3 years ago
What is the pH of a solution with [OH-]= (9.00x10^-4)? Enter your answer in scientific notation and with three signigicant figur
anygoal [31]

Hey there!:

Given [ OH⁻ ] = 9.00 x 10⁻⁴

We know that : [H⁺ ] [OH⁻ ] = 1 x 10⁻¹⁴

Thus [H⁺ ] =  ( 1 x 10⁻¹⁴ ) / ( 9.00 x 10⁻⁴ )

[ H⁺ ] = 1 x 10⁻¹¹ M

therefore:

pH = - log [ H⁺ ]

pH = - log [ 1 x 10⁻¹¹ ]

pH = 10.95

Therfore pH = 10.95

I hope this will help !

7 0
4 years ago
How is the scientific definition of "heat" different from how we use it every day? PLEASE NEED THE ANSWER ASAP
klio [65]
Heat is energy, that can be transferred to another item, which is “less hot”.
3 0
3 years ago
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