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2 years ago

Hypothesis: How will molecular size affect the rate of evaporation and how will this correlate

1 answer:

5 0

A molecular size affects the rate of evaporation when the larger the intermolecular forces in a compound, the slower the evaporation rate and this correlates with temperature change.

Molecular size seems to have an effect on evaporation rates in that the larger a molecule gets or grows from a base chemical formula, its evaporation rate will get slower.

<h3>What is the molecular size?</h3>

This is a measure of the area a molecule occupies in three-dimensional space as this relates to the physical size of an individual molecule.

Hence, we can see that a molecular size affects the rate of evaporation the larger the forces, the lower the rate.

Read more about molecular size here:

brainly.com/question/16616599

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At a certain temperature the vapor pressure of pure heptane C7H16 is measured to be 454.mmHg. Suppose a solution is prepared by

OlgaM077 [116]

Answer:

Mass of heptane = 102g

Vapor pressure of heptane = 454mmHg

Molar mass of heptane = 100.21

No of mole of heptane = mass/molar mass = 102/100.21

No of mole of heptane = 1.0179

Therefore the partial pressure of heptane = no of mole heptane *Vapor pressure of heptane

Partial pressure of heptane = 1.0179*454mmHg

Partial pressure of heptane = 462.1096 = 462mmHg

the partial pressure of heptane vapor above this solution = 462mmHg

5 0

3 years ago

A mixture of compounds containing diethylamine, phenol, ammonia, and acetic acid is separated using liquid-liquid extraction as

umka2103 [35]

Answer:

I would expect to extract the acetic acid.

Explanation:

In the first step, since we are adding a concentrated acid, it will react with the bases present in the mixture (diethylamine and ammonia) forming salts, which are soluble in water. Therefore, after draining the aqueous layer, we will have phenol and acetic acid left in the organic layer.

In the second step, we are adding a diluted base, so it will react with a strong acid. This compound is acetic acid, and its salt will be present in the aqueous layer. Phenol will be left on the organic layer.

7 0

3 years ago

A 76.00-pound flask of mercury costs $151.50. The density of mercury is 13.534 g/cm3.

Agata [3.3K]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Please see below solution:

1 lb Hg x (151.50/76 lb) = cost of 1 lb.
cost 1 lb x (1g/453.6 g) = cost of 1 g.

8 0

2 years ago

Read 2 more answers

What is the volume of a substance that has a density of 13.6 g/cm and a mass of 3.0 g?

MakcuM [25]

Answer:

$\boxed {\boxed {\sf v \approx 0.22 \ cm^3}}$

Explanation:

We are asked to find the volume of a substance.

We are given the density and the mass. The density of a substance is its mass per unit volume. The formula for calculating density is:

$\rho= \frac{m}{v}$

We know the density of the substance is 13.6 grams per cubic centimeter and the mass is 3.0 grams.

ρ= 13.6 g/cm³
m= 3.0 g

Substitute these values into the formula.

$13.6 \ g/cm^3= \frac{3.0 \ g }{v}$

We are solving for the volume, so we must isolate the variable v. First, cross multiply. Multiply the first numerator by the second denominator, then multiply the first denominator by the second numerator.

$\frac{13.6 \ g/cm^3}{1}= \frac{3.0 \ g }{v}$

$13.6 \ g/cm^3 *v =3.0 \ g *1$

Multiply on the right side of the equation.

$13.6 \ g/cm^3 *v =3.0 \ g$

The variable is being multiplied by 13.6 grams per cubic centimeters. The inverse operation of multiplication is division, so we divide both sides of the equation by 13.6 g/cm².

$\frac {13.6 \ g/cm^3 *v}{13.6 \ g/cm^3} =\frac{3.0 \ g }{13.6 \ g/cm^3}$

$v =\frac{3.0 \ g }{13.6 \ g/cm^3}$

The units of grams cancel.

$v =\frac{3.0 }{13.6 \ cm^3}$

$v= 0.2205882353 \ cm^3$

The original measurement of density has 3 significant figures and the measurement of mass has 2. Our answer must have the least number of sig figs, which is 2. For the number we found, that is the hundredth place. The 0 in the thousandth place tells us to leave the 2 in the hundredth place.

$v \approx 0.22 \ cm^3$

The volume of the substance is approximately 0.22 cubic centimeters.

6 0

3 years ago

Give me an example of lustre that is shiny and dull.

Alex

The state or quality of shining by reflecting light; glitter, sparkle, sheen, or gloss such as ornaments shiny and dull

3 0

3 years ago