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2 years ago

Hypothesis: How will molecular size affect the rate of evaporation and how will this correlate

1 answer:

5 0

A molecular size affects the rate of evaporation when the larger the intermolecular forces in a compound, the slower the evaporation rate and this correlates with temperature change.

Molecular size seems to have an effect on evaporation rates in that the larger a molecule gets or grows from a base chemical formula, its evaporation rate will get slower.

<h3>What is the molecular size?</h3>

This is a measure of the area a molecule occupies in three-dimensional space as this relates to the physical size of an individual molecule.

Hence, we can see that a molecular size affects the rate of evaporation the larger the forces, the lower the rate.

Read more about<em> molecular size</em> here:

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Gaseous butane, CH3(CH2)2CH, reacts with gaseous oxygen gas, O2, to produce gaseous carbon dioxide, CO2, and gaseous water, H2O.

weeeeeb [17]

Answer:

Percentage yield of carbon dioxide is 49.9%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3(CH2)2CH3 + 13O2 —> 8CO2 + 10H2O

2C4H10 + 13O2 —> 8CO2 + 10H2O

Next, we shall determine the masses of butane and oxygen that reacted and the mass of carbon dioxide produced from the balanced equation. This is illustrated below:

Molar mass of butane C4H10 = (12×4) + (10×1)

= 48 + 10

= 58 g/mol

Mass of C4H10 from the balanced equation = 2 × 58 = 116 g

Molar mass of O2 = 16 × 2 = 32 g/mol

Mass of O2 from the balanced equation = 13 × 32 = 416 g

Molar mass of CO2 = 12 + (16×2)

= 12 + 32

= 44 g/mol

Mass of CO2 from the balanced equation = 8 × 44 = 352 g

Summary:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen to produce 352 g of carbon dioxide.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen.

Therefore, 34.29 g of butane will react with = (34.29 × 416) / 116 = 122.97 g of oxygen.

From the calculation made above, we can see clearly that only 122.97 g out of 165.7 g of oxygen reacted completely with 34.29 g of butane. Therefore, butane is the limiting reactant and oxygen is the excess reactant.

Next, we shall determine the theoretical yield of carbon dioxide.

In this case, we shall use the limiting reactant because it will give the maximum yield of carbon dioxide as all of it is used up in the reaction.

The limiting reactant is butane and the theoretical yield of carbon dioxide can be obtained as follow:

From the balanced equation above,

116 g of butane reacted to produce 352 g of carbon dioxide.

Therefore, 34.29 g of butane will react to produce = (34.29 × 352) / 116 = 104.05 g of carbon dioxide.

Therefore, the theoretical yield of carbon dioxide is 104.05 g

Finally, we shall determine the percentage yield of carbon dioxide as follow:

Actual yield of carbon dioxide = 51.9 g

Theoretical yield of carbon dioxide = 104.05 g

Percentage yield of carbon dioxide =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield of carbon dioxide = 51.9 / 104.05 × 100

Percentage yield of carbon dioxide = 49.9%

7 0

3 years ago

If 27.5 mL of 16.0 M nitric acid stock solution is added to 300. mL of water, what is the molarity of the diluted solution?

pochemuha

Answer:

0.72M

Explanation:

=30*12/500

=0.72M

8 0

3 years ago

How many moles of AgNO3 must react to form 0. 854 mol Ag? mol AgNO3.

babunello [35]

The moles of silver nitrate required to form 0.854 mol silver ion has been 0.854 mol.

The balanced chemical equation for the dissolution of silver nitrate has been:

$\rm AgNO_3\;\rightarrow\;Ag^+\;+\;NO_3^-$

The aqueous solution of silver nitrate has been dissociated into the constituent silver and nitrate ions.

In a balanced chemical equation, the coefficient has been equivalent to the moles of each reactant forming the moles of product.

From, the balanced equation,

$\rm 1\;mol\;AgNO_3=1\;mol\;Ag$

The given moles of Silver has been 0.854 mol. Thus, the moles of silver nitrate required has been given as:

$\rm 1\;mol\;Ag^+=1\;mol\;AgNO_3\\0.854\;mol\;Ag^+=0.854\;\times\;1\;mol\;AgNO_3\\0.854\;mol\;Ag^+=0.854\;mol\;AgNO_3$

The moles of silver nitrate required to form 0.854 mol silver ion has been 0.854 mol.

For more information about the moles produced, refer to the link:

brainly.com/question/10606802

6 0

2 years ago

What are the Sub atomic particles?

rusak2 [61]

A particle which is smaller than an atom in size. Typically, an atom can be broken down into three subatomic particles, namely: protons, electrons, and neutrons.

6 0

3 years ago

Incomplete dash of fuels produces many poisonous dash

tangare [24]

Answer:

Incomplete combustion of fuels produces a very poisonous gas called carbon monoxide:Excessive inhaling of carbon dioxide gas can kill a person.

I don't know if this is correct, your question did not have much context.

6 0

3 years ago