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3 years ago

What is the mass of 2.80 grams of H2O

Chemistry

1 answer:

IrinaK [193]3 years ago

8 0

The mass of 2.80 grams of h2o is 18.02 amu I believe

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What ion must be present for a compound to be considered a base?

Alexeev081 [22]

It is OH- (hydroxide ion)

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3 years ago

Which line segment on the graph represents boiling

hoa [83]

1. There is no graph given

2. ENERGY LEVELS!!!

Boiling is the process of liquid(middle energy, flat line) turning into a gas(lots of energy, flat line), hope this helps

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3 years ago

Friction is the force that occurs when: A. one object attracts or repels another. B. one object is rubbing against another. C. o

AlladinOne [14]

Answer:

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3 years ago

Read 2 more answers

What is the value for AG at 5000 K if AH = -220 kJ/mol and S= -0.05 kJ/(mol-K)?

Serhud [2]

Answer:

C. 30 kJ

Explanation:

Hello there!

In this case, in agreement to the thermodynamic definition of the Gibbs free energy, in terms of enthalpy of entropy:

$\Delta G= \Delta H-T\Delta S$

It is possible to calculate the required G by plugging in the given entropy and enthalpy as shown below:

$\Delta G=-220kJ/mol-5000K*-0.05kJ/mol*K\\\\\Delta G=30kJ/mol$

Therefore, the answer is C. 30 kJ .

Best regards!

4 0

2 years ago

An airplane travels 2100 km at 1000km/hE. It encounters a wind and slows to 800 km/h E for the next 1300 km. What is the average

Deffense [45]

Answer:

The average velocity of the airplane for this trip is 1684.21 km/h

Explanation:

Average velocity is the rate of change of displacement with time. That is,

Average velocity = $\frac{Displacement }{Change in time}$ = Δx / Δt = $\frac{x2 - x1}{t2 - t1}$

Now we will calculate the time taken by the airplane for the first motion before it encounters a wind.

From,

Velocity = $\frac{Distance traveled}{Time taken}$

Time = $\frac{Distance traveled}{Velocity}$

Therefore, Time = $\frac{2100km }{1000km/h}$

Time = 2.1h

This is the time taken before the airplane encounters a wind.

Hence, t1 = 2.1h

Now, For the time taken by the airplane when it encounters a wind

Also from,

Velocity = $\frac{Distance traveled}{Time taken}$

Time = $\frac{Distance traveled}{Velocity}$

Therefore, Time = $\frac{1300km }{800km/h}$

Time = 1.625h

Hence, t2 = 1.625h

Now, to calculate the average velocity

Average velocity = $\frac{x2 - x1}{t2 - t1}$

x1= 2100, x2= 1300, t1= 2.1h and t2= 1.625h

Hence, Average velocity = $\frac{1300 - 2100}{1.625 - 2.1}$

Average velocity = 1684.21 km/h

7 0

3 years ago