Question

What is the energy change when 100g of Benzene boils at 80.1°C?

Answer 1

The enthalpy of vaporization for Benzene is 30.8 kJ/mol. 39.42 kJ is the energy change when 100g of Benzene boils at 80.1 degrees Celsius.

What is Enthalpy of Vaporization ?

The amount of enthalpy or energy that must be added to a liquid substance into gas substance is called Enthalpy of Vaporization. It is also known as Latent heat of vaporization.

How to find the energy change from enthalpy of vaporization ?

To calculate the energy use this expression:

$Q = n \Delta H_{\text{vapo.}$

where,

Q = Energy change

n = number of moles

$\Delta H_{\text{Vapo.}}$ = Molar enthalpy of vaporization

Now find the number of moles

Number of moles (n) = $\frac{\text{Given Mass}}{\text{Molar mass}}$

                                   = $\frac{100\ g }{78\ g/mol}$

                                   = 1.28 mol

Now put the values in above formula we get

$Q = n \Delta H_{\text{vapo.}$

   = 1.28 mol × 30.8 kJ/mol

   = 39.42 kJ

Thus from the above conclusion we can say that The enthalpy of vaporization for Benzene is 30.8 kJ/mol. 39.42 kJ is the energy change when 100g of Benzene boils at 80.1 degrees Celsius.

Learn more about the Enthalpy of Vaporization here: brainly.com/question/13776849

#SPJ1

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: The enthalpy of vaporization for Benzene is 30.8 kJ/mol. What is the energy change when 100g of Benzene boils at 80.1 degrees Celsius?