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Vlad1618 [11]
2 years ago
14

A geologist finds that a Moon rock whose mass is 8.94 kg has an apparent mass of 6.18 kg when submerged in water. What is the de

nsity of the rock
Physics
1 answer:
Grace [21]2 years ago
4 0

Density of rock = 3.23 Kg/m^3

Given:

mass of Moon rock = 8.94 kg

apparent mass of Moon rock = 6.18 kg

To Find:

density of the rock

Solution: It is a universal fact that mass of an object remains constant whether measured on earth or on moon.

Mass of rock on moon/earth = 8.94 kg

When the block is immersed in water then;

Loss in weight = weight of water displaced

Loss in weight = 8.94 - 6.18 = 2.76 kg

As we know that water has a density of 1g/cm^3 (1000kg/m^3)

Volume of water = volume of the rock = Mass/density = 2.76 kg

density of rock mass/volume = 8.94/2.76 = 3.23 Kg/m^3

Density of rock = 3.23 Kg/m^3

Learn more about Density here:

brainly.com/question/1354972

#SPJ4

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A car travels initially at 24 m/s, until it enters the highway. If the car accelerates at 4 m/s^2 for a 96 meters, what is the c
marishachu [46]
  • initial velocity=u=24m/s
  • Acceleration=a=4m/s^2
  • Distance=s=96m
  • Final velocity=v

Using 3rd equation of kinematics

\boxed{\Large{\sf v^2-u^2=2as}}

\\ \Large\sf\longmapsto v^2=u^2+2as

\\ \Large\sf\longmapsto v^2=24^2+2(4)(96)

\\ \Large\sf\longmapsto v^2=576+768

\\ \Large\sf\longmapsto v^2=1344

\\ \Large\sf\longmapsto v=\sqrt{1344}

\\ \Large\sf\longmapsto v=36.6m/s

3 0
3 years ago
The membrane that surrounds a certain type of living cell has a surface area of 4.3 x 10-9 m2 and a thickness of 1.1 x 10-8 m. A
Nadusha1986 [10]

Answer:

The charge resides on the outer surface = 1.245 \times 10^{-12} C

Explanation:

Surface area of cell  (A) = 4.3\times 10^{-9}  m^{2}

Separation between two plate  (d) = 1.1 \times 10^{-8}  m  

Dielectric constant (k) = 4.2

Potential difference (\Delta V) = 85.7 \times 10^{-3} V

The capacitance of parallel plate capacitor in free space is given by,

           C = \frac{\epsilon_{o} A }{d}

Where \epsilon_{o}  = permittivity of free space = 8.85 \times 10^{-12}

The Capacitance of capacitor is increase by k times when it placed in dielectric medium.

C_{dielectric}  = \frac{k \epsilon_{o} A }{d}

And we know that, C = \frac{Q}{ \Delta V}

So charge on the outer surface is given by,

      Q = \frac{k \epsilon A \Delta V }{d}

      Q = \frac{4.2 \times 4.3 \times 10^{-9} \times 8.85 \times 10^{-12} \times 85.7\times 10^{-3}   }{1.1 \times 10^{-8} }

      Q = 1.245 \times 10^{-12}

3 0
3 years ago
Eric drops a 2.20 kg water balloon that falls a distance of 45.08 m off the top of a
Marianna [84]

Answer:

972 J

Explanation:

At the bottom, all the gravitational potential energy was converted into kinetic energy. If you calculate the GPE, its value will be the same that the KE at the bottom. The GPE can be calculated this way:

GPE = mass×gravity×heigth

GPE = 2.2×9.8×45.08 ≈ 972

4 0
2 years ago
A book falling to the floor is best described by: law one, law two, law three, or all three laws?
Law Incorporation [45]

The book falling to the floor is described by Newton's second law and Newton's third law

Explanation:

Newton's first law of motion states that:

"An object moving at constant velocity (or at rest) keeps moving at constant velocity (or will stay at rest) unless acted upon unbalanced, external forces"

For a book falling to the floor, there is an unbalanced force acting on it (the  force of gravity): therefore, we cannot apply Newton's first law.

Newton's second law of motion states that:

"The net force acting on an object is equal to the product between the object's mass, m, and its acceleration, a"

Mathematically:

F=ma

For the book falling to the floor, F is the force of gravity; therefore, we can apply Newton's second law, and in this case it tells us that the book has a non-zero acceleration during its fall.

In particular, the force of gravity is F=mg (where g is the acceleration due to gravity), so the acceleration of the book is

mg=ma\\a=g=9.8 m/s^2

Newton's third law of motion states that:

"When an object A exerts a force (action force) on an object B, then object B exerts an equal and opposite  force (reaction force) on object A".

In this case, the Earth is exerting a  force (the force of gravity) on the book during its fall: therefore, the book is also exerting a equal and opposite force (reaction force) on the Earth.

Learn more about Newton laws of motion:

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4 0
3 years ago
A swan on a lake gets airborne by flapping its wings and running on top of the water. If the swan must reach a velocity of 6.00
ira [324]

Answer:

A. 51.42 m.

B. 17.14 s.

Explanation:

Using equations of motion:

vf^2 = vi^2 + 2 * aS

Where,

vf = final velocity

a = acceleration

S = distance to which swan traveled

vi = 0 m/s

6.00^2 = 2 * 0.350S

S = 36/0.7

= 51.42 m.

B.

vf = vi + at

6 = 0 + 0.35t

t = 6/0.35

= 17.14 s.

5 0
3 years ago
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