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Vlad1618 [11]
1 year ago
14

A geologist finds that a Moon rock whose mass is 8.94 kg has an apparent mass of 6.18 kg when submerged in water. What is the de

nsity of the rock
Physics
1 answer:
Grace [21]1 year ago
4 0

Density of rock = 3.23 Kg/m^3

Given:

mass of Moon rock = 8.94 kg

apparent mass of Moon rock = 6.18 kg

To Find:

density of the rock

Solution: It is a universal fact that mass of an object remains constant whether measured on earth or on moon.

Mass of rock on moon/earth = 8.94 kg

When the block is immersed in water then;

Loss in weight = weight of water displaced

Loss in weight = 8.94 - 6.18 = 2.76 kg

As we know that water has a density of 1g/cm^3 (1000kg/m^3)

Volume of water = volume of the rock = Mass/density = 2.76 kg

density of rock mass/volume = 8.94/2.76 = 3.23 Kg/m^3

Density of rock = 3.23 Kg/m^3

Learn more about Density here:

brainly.com/question/1354972

#SPJ4

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geniusboy [140]

Volume= Length X width X height.

Plug in the values for each and solve for the volume.

V= (L)(W)(H)

V=(4cm)(5cm)(10cm).


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3 years ago
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Luba_88 [7]
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Valerie is preparing a blood sample for analysis. She wants to separate the solid red blood cells and obtain only the liquid por
liraira [26]
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3 years ago
Read 2 more answers
An object of mass 20 kg is raised vertically through a distance of 8 m above ground level. If g = 10 m/s2, what is the gravitati
IgorC [24]

2400joules

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P.E

m= 20kg h=8m g=10m

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6 0
2 years ago
Q1: A cyclist brakes to a stop. His thinking distance was 1m and his braking distance was 3m. What was his overall stopping dist
weeeeeb [17]

Answer:

1.) 4m

2.) 37 m

3.) 62m

4.) 2.5 s

Explanation:

1.) Given that the

Thinking distance = 1m

Breaking distance = 3m

Stopping distance = breaking distance + thinking distance

Stopping distance = 1 + 3 = 4m

2.) Given that the

Stopping distance = 52 m

Thinking distance = 15m

Breaking distance = 52 - 15 = 37m

3.) The stopping distance = 76m

Thinking distance = 14m

Breaking distance = 76 - 14 = 62m

It take the brakes 62m to slow the car down to a stop.

4.) Given that a lorry travels 28m when stopping from a speed of 4m/s. If its braking distance was 18m, what was the driver’s reaction time?

Thinking = stopping distance - braking distance

Thinking distance = 28 - 18 = 10m

Speed = distance/time

4 = 10/reaction time

Reaction time = 10/4

Reaction time = 2.5 s

5.) Question incomplete

5 0
3 years ago
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