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3 years ago

In which changes of state do atoms lose energy

1 answer:

6 0

Yeah, it's every state. Atoms need a certain quanta of energy to jump to each state of energy, and therefore change state depending on how much energy is absorbed and/or released. This applies to all states of matter.

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0.A 20-g bullet moving at 1 000 m/s is fired through a one-kg block of wood emerging at a speed of 100 m/s. What is the kinetic

Fiesta28 [93]

Answer:

KE = 0.162 KJ

Explanation:

given,

mass of bullet (m)= 20 g = 0.02 Kg

speed of the bullet (u)= 1000 m/s

mass of block(M) = 1 Kg

velocity of bullet after collision (v)= 100 m/s

kinetic energy = ?

using conservation of momentum

m u = m v + M V

0.02 x 1000 = 0.02 x 100 + 1 x V

20 = 2 + V

V = 18 m/s

now,

Kinetic energy of the block

$KE = \dfrac{1}{2}mv^2$

$KE = \dfrac{1}{2}\times 1 \times 18^2$

KE = 162 J

KE = 0.162 KJ

4 0

3 years ago

The space shuttle orbits 310 km above the surface of the Earth.

MAVERICK [17]

Answer:

44.7 N

Explanation:

The gravitational force between the objects is given by:

$F=G\frac{mM}{r^2}$

where

G is the gravitational constant

m and M are the masses of the two objects

r is the distance between the centres of the two objects

In this problem, we have:

$m=5.0 kg$ is the mass of the sphere

$M=5.98\cdot 10^{24} kg$ is the Earth's mass

$R=6370 km$ is the Earth's radius, while h=310 km is the altitude of the sphere, so the distance of the sphere from Earth's centre is

$r=6370 km+310 km=6680 km=6.68\cdot 10^6 m$

Substituting into the equation, we find

$F=(6.67\cdot 10^{-11})\frac{(5.0 kg)(5.98\cdot 10^{24} kg)}{(6.68\cdot 10^6 m)^2}=44.7 N$

8 0

3 years ago

At which point is the object not moving?

Alenkinab [10]

It’s none of those because it’s moving at a constant rate

8 0

3 years ago

Light passes through a 0.15 mm-wide slit and forms a diffraction pattern on a screen 1.25 m behind the slit. The width of the ce

Elena L [17]

Answer:

The value is $\lambda = 900 \ nm$

Explanation:

From the question we are told that

The width of the slit is $a = 0.15 \ mm = 0.00015 \ m$

The distance of the screen from the slit is D = 1.25 m

The width of the central maximum is $y = 0.75 \ cm = 0.0075 \ m$

Generally the width of the central maximum is mathematically represented as

$y = \frac{m * D * \lambda}{a}$

Here m is the order of the fringe and given that we are considering the central maximum, the order will be m = 1 because the with of the central maximum separate's the and first maxima

$\lambda = \frac{a y}{ m * D }$

=> $\lambda = \frac{ 0.000015 * 0.0075}{ 1 * 1.2 }$

=> $\lambda = 900 *10^{-9} \ m$

=> $\lambda = 900 \ nm$

6 0

3 years ago

AlexFokin [52]

Each planet orbiting our sun is unique. Yet the four inner planets have much in common. Mercury, Venus, Earth and Mars are terrestrial or telluric planets. They are rocky with a dense metal core consisting mostly of iron. Planetary scientists theorize that Mars and Venus may once have had conditions like Earth's, favorable to life. The name "terrestrial" comes from the Latin word "terra," which means land. There are at least four Jovian or gas planets in our solar system. Jovian planets such as Jupiter, Saturn, Uranus and Neptune are large planets that are composed of light materials such as hydrogen and helium. The name "Jovian" comes from the planets' resemblance to Jupiter. The moniker "gas planet" is slightly misleading, since the interior of these frigid planets is gas supercooled to a liquid state.

8 0

3 years ago