1. By predicting the path of hurricanes, it is possible to warn people in its prospective path in advance. This way lives can be saved. In addition economic cost. associated with its destruction, can be minimized by bracing in advance for the storm along its path.
2. When the sea temperatures increase, there is increased vaporization of water into the atmosphere. This causes a transfer of heat into the atmosphere from the hydrosphere. This causes a drop of pressure in the local region that is one ingredient associated with the beginning of a hurricane.
3. The more the humidity, it means the more the heat transfer to the atmosphere through condensation. This reduces the pressure proportionally with the amount of humidity. This low pressure is an ingredient for hurricanes. In addition, the higher the humidity the larger the clouds and the larger the thunderstorms and precipitation associated with the hurricane
4. Winds drive hurricanes and determines their vicious force. In the formation of the hurricane, low winds are required to allow the formation of the funnel at the front betwen the cold and warm air masses. Winds blowing in congruence with the hurricane after then make it stronger while those that blow against it weaken it.
5. The answer is; YES, I would expect a hurricane. This is because at 12 0 N and 45 0 W are the open oceans of the Pacific. The average sea temperaturs in summer is between 15 0 and 20 0. At 27.5 0, this increases the humidity at the local region and therefore the tranfer of heat to the atmsphere. The light breeze gives the stability required for the air convection currents to occur forming a funnel front between the air masses.
Explanation:
Below is an attachment containing the solution.
Answer:
a.v=u+v/2
a.v=s/t
combining two equation we get,
u+v/2=s/t
(u+v)t/2=s
(u+v)t/2=s
{u+(u+at)}t/2=s
(u+u+at)t/2=s
(2u+at)t/2=s
2ut+at^2/2=s
2ut/2+at^2/2=s
UT +1/2at^2=s
proved
a=v-u/t
at=v-u
u+at=v
F=ma so a=F/m
ax=180/270=0.67m/s^2
ay=390/270=1.44m/s^2
Magnitude = sqrt((0.67^2)+(1.44^2))=1.59m/s^2
Direction- Tan(x)=0.67/1.44=0.47 Tan^-1(x)=25 degrees
Answer:
Change in momentum will be -4.4 kgm/sec
So option (A) is correct option
Explanation:
Mass of the ball is given m = 0.10 kg
Initial velocity of ball 
And velocity after rebound 
We have to find the change in momentum
So change in momentum is equal to 
( here negative sign shows only direction )
So option (A) will be correct answer
