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DaniilM [7]
2 years ago
5

Energy released by the sun results from the process where atomic nuclei

Physics
1 answer:
Ray Of Light [21]2 years ago
6 0

Answer:

b) combine

Explanation:

The energy from the sun is due to Nuclear Fusion where lighter nuclei combine to form heavier and stable nuclei this releasing a lot of energy in this process.

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On a different planet, a ball is fired straight upwards from the ground with an initial speed of 100 m/s. At the same instant, a
tensa zangetsu [6.8K]

Answer:

g = 25 m/s²

Explanation:

Since, the balls meet at the exact instant when upward thrown ball reaches its maximum point. Therefore, applying 1st equation of motion to it, we get:

Vf₁ = Vi₁ + gt

where,

g = -g (for upward motion) = acceleration due to gravity at that planet = ?

t = time

Vf₁ = Final Velocity of Upward Thrown ball = 0 m/s (ball stops at highest point)

Vi₁ = Initial Velocity of Upward Thrown Ball = 100 m/s

Therefore,

0 m/s = 100 m/s - gt

gt = 100 m/s  ------------- equation 1

Now, applying 3rd equation of motion for the height covered:

2(-g)h₁ = Vf₁² - Vi₁²

h₁ = 10000/2g

Now, we apply 2nd equation of motion to second ball moving downward:

h₂ = Vi₂t + (0.5)gt²

where,

h₂ = height covered by second ball at the time of meeting

Vi₂ = initial velocity of second ball = 0 m/s (since, it starts from rest)

Therefore,

h₂ = (0)(t) + (0.5)gt²

h₂ = (0.5)gt²

Now, it is clear from the given condition, that when the two balls meet, the sum of distance covered  by both the balls will be equal to 400 m. Therefore,

h₁ + h₂ = 400 m

using values:

10000/2g + (0.5)gt² = 400

10000 + g²t² = (400)(2g)

using equation 1:

10000 + (100)² = 800g

g = 20000/800

<u>g = 25 m/s²</u>

7 0
3 years ago
Listed following are three possible models for the long-term expansion (and possible contraction) of the universe in the absence
Lynna [10]

Answer:

1) Recollapsing universe

2) critical universe

3) Coasting universe

Explanation:

According to the smallest ration (ratio actual mass density to current density) to largest ration, rank of models for expansion of universe are

1) Recollapsing universe -in this, metric expansion of space is reverse and universe recollapses.

2) critical universe - in this, expansion of universe is very low.

3) Coasting universe -  in this, expansion of universe is steady and uniform

6 0
3 years ago
What effects are jets and magnetic fields thought to have on a protostar?
alexgriva [62]

Answer:

the effects that a jet and the magnetic fields have on a ProStar Is :

Explanation:

over the years scientist have found out that magnetic fields and the Jets carry away angular momentum , which helps the ProStar grow more in size .

7 0
3 years ago
A ball rolls of a cliff and when it lands has a vertical velocity 35 ms ^-1. how high was the cliff?
Licemer1 [7]
Using V²=u² +2gH
let's assume the ball falls from rest, then it's initial velocity = 0ms-¹ (U=0)
then from the above info V= 35ms-¹
g= 10ms-² (value of acceleration due to gravity to the nearest tens)

so input your values above into the given formula to find height
35² = 0² +2×10×H
1225 = 20H
H = 1225÷20 = 61.25m
6 0
4 years ago
Calculate the magnitude of the electric field at one corner of a square 2.42 m on a side if the other three corners are occupied
Karolina [17]

Ans:

12500 N/C

Explanation:

Side of square,  a = 2.42 m

q = 4.25 x 10^-6 C

The formula for the electric field is given by

E = \frac{Kq}{r^2}

where, K be the constant = 9 x 10^9 Nm^2/c^2 and r be the distance between the two charges

According to the diagram

BD = \sqrt{2}\times a

where, a be the side of the square

So, Electric field at B due to charge at A

E_{A}=\frac{Kq}{a^2}

E_{A}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2.42^2}

EA = 6531.32 N/C

Electric field at B due to charge at C

E_{C}=\frac{Kq}{a^2}

E_{C}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2.42^2}

Ec = 6531.32 N/C

Electric field at B due to charge at D

E_{D}=\frac{Kq}{2a^2}

E_{D}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2\times 2.42^2}

ED = 3265.66 N/C

Now resolve the components along X axis and Y axis

Ex = EA + ED Cos 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C

Ey = Ec + ED Sin 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C

The resultant electric field at B is given by

E=\sqrt{E_{x}^{2}+E_{y}^{2}}

E=\sqrt{8840.5^{2}+8840.5^{2}}

E = 12500 N/C

Explanation:

8 0
4 years ago
Read 2 more answers
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