The frequency of a wave is equal to the linear speed divided the wavelength. so in equation form.
f = v / l
so the wavlength
l = v / f
where f is the frequency
v iss the linear speed
l is the wavelength
l = ( 5100 m/s ) / ( 2.2 Mhz ) ( 10^6 hz / 1 Mhz )
f = 0.0023 m
f = 2.3 mm
The characteristics of the speed of the traveling waves allows to find the result for the tension in the string is:
T = 10 N
The speed of a wave on a string is given by the relationship.
v =
Where v es the velocty, t is the tension ang μ is the lineal density.
They indicate that the length of the string is L = 2.28 m and the pulse makes 4 trips in a time of t = 0.849 s, since the speed of the pulse in the string is constant, we can use the uniform motion ratio, where the distance traveled e 4 L
v = 
v = 
v = 
v = 10.7 m / s
Let's find the linear density of the string, which is the length of the mass divided by its mass.
μ = 
μ = 8.77 10⁻² kg / m
The tension is:
T = v² μ
Let's calculate
T = 10.7² 8.77 10⁻²
T = 1 0 N
In conclusion using the characteristics of the velocity of the traveling waves we can find the result for the tension in the string is:
T = 10 N
Learn more here: brainly.com/question/12545155
Answer:
The answer is C.
Explanation:
An ion is unlike a neutral atom in the fact that it has a charge. Because electrons are negatively charged, an atom becomes more positive if electrons are lost.
Answer:
a) τmax = 586.78 P.S.I.
b) σmax = 15942.23 P.S.I
Explanation:
D = 3.81 in
d = 3.24 in
P = 930 lb
L = 3.7 ft = 44.4 in
a) The maximum horizontal shear stress can be obtained as follows
τ = V*Q / (t*I)
where
V = P = 930 lb
Q = (2/3)*(R³- r³) = (1/12)*(D³- d³) = (1/12)*((3.81 in)³- (3.24 in)³)
⇒ Q = 1.7745 in³
t = D - d = 3.81 in - 3.24 in = 0.57 in
I = (π/64)*(D⁴-d⁴) = (π/64)*((3.81 in)⁴- (3.24 in)⁴) = 4.9341 in⁴
then
τ = (930 lb)*(1.7745 in³) / (0.57 in*4.9341 in⁴)
⇒ τmax = 586.78 P.S.I.
b) We can apply the following equation in order to get the maximum tension bending stress in the pipe
σmax = Mmax *y / I
where
Mmax = P*L = 930 lb*44.4 in = 41292 lb-in
y = D/2 = 3.81 in /2 = 1.905 in
I = 4.9341 in⁴
then
σmax = (41292 lb-in)*(1.905 in) / (4.9341 in⁴) = 15942.23 P.S.I
