Question:
A. Engineer A: "When the sample alpha decays, it will give off alpha particles. These will
trigger a photosensor (a device that senses forms of light) that will open the lock."
B. Engineer B: "When the sample alpha decays, it only releases large amounts of heat.
This will trigger a thermometer that will open the lock."
C. Engineer C: "When the sample alpha decays, it will lose mass, This will trigger a scale
that will open the lock."
D. Engineer D: "When the sample alpha decays, it will give off negatively charged alpha
particles. Because alpha particles are electrons, they will complete a circuit that will
open the lock."
Answer:
The correct option is;
A. Engineer A: "When the sample alpha decays, it will give off alpha particles. These will trigger a photosensor ( a device that senses forms of light) that will open the lock"
Explanation:
Here, we note that in alpha decay (α-decay) there is an emission of an alpha particle or helium nucleus with the transformation of the parent element nucleus into that of a different element, having reduced mass and atomic numbers
Alpha particles are a form of ionizing radiation with a mass of 6.64 × 10⁻²⁷ kg and therefore they can be sensed by a photo sensor but will be slowly sensed by a scale.
Answer:C) car X
Explanation:
Given
All the cars have identical Engine thus Force Produced by car X will be equal to Y and Z
and
Since Car X is most massive so acceleration associated with it will be minimum
acceleration of car X is minimum thus it will travel farthest
Answer:
A. It must be zero
Explanation:
A spacecraft leaves the solar system at a velocity of 1,500 m/s. The net force on this spacecraft is zero. What can we say about the spacecraft's acceleration?
According to Newton's second law
Force = Mass × acceleration
If the net force is zero
0 = mass × acceleration
0 = ma
a = 0/m
a = 0m/s²
this shows that the acceleration will be zero If the net force is zero
Answer:
Explanation:
We can calculate the acceleration experimented by the passenger using the formula , taking the initial direction of movement as the positive direction and considering it comes to a rest:
Then we use Newton's 2nd Law to calculate the force the passenger of mass m experimented to have this acceleration:
Which for our values is:
Answer:
The second system must be set in motion seconds later
Explanation:
The oscillation time, T, for a mass, m, attached to spring with Hooke's constant, k, is:
One oscillation takes T secondes, and that is equivalent to a 2π phase. Then, a difference phase of π/2=2π/4, is equivalent to a time t=T/4.
If the phase difference π/2 of the second system relative to the first oscillator. The second system must be set in motion seconds later