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ANEK [815]
4 years ago
12

When blood passes through the lungs, carbon dioxide and water are formed from carbonic acid dissolved in the blood. The carbon d

ioxide formed passes into the lungs and is exhaled. H2CO3 H2O + CO2 What kind of reaction has occurred? combustion, combination decomposition, single-replacement, double-replacement
Chemistry
2 answers:
NISA [10]4 years ago
8 0

Answer:

for plato its C, decomposition

Explanation:

NeTakaya4 years ago
7 0
Answer is: <span>decomposition.

Balanced chemical reaction: H</span>₂CO₃ → CO₂ + H₂O.
H₂CO₃ is carbonic acid.
CO₂ is carbon (IV) oxide or carbon dioxide.<span>
Chemical decomposition is the separation of a single chemical compound (in this example </span>carbonic acid<span>) into its two or more simpler compounds (in this example water and carbon dioxide).</span>
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What are adipoyl chloride used for or uses?
Alexxandr [17]

Answer:

Explanation:

It is a colorless liquid. It reacts with water to give adipic acid. It is prepared by treatment of adipic acid with thionyl chloride.

Adipoyl Chloride can be used in the synthesis of nylon. Also it is used in the synthesis of chiral polymer for membrane application.

3 0
3 years ago
the valence electrons of an atom of which element would feel a smaller effective nuclear charge than the valence electrons of a
Dvinal [7]
D. Strontium is the right answer
5 0
4 years ago
In an experiment, a 0.5297 g sample of diphenylacetylene (C14H10) is burned completely in a bomb calorimeter. The calorimeter is
V125BC [204]

Answer:

the Molar heat of  Combustion  of  diphenylacetylene (C_{14}H_{10})  = -6.931 *10^3 \ kJ/mol

Explanation:

Given that:

mass of diphenylacetylene (C_{14}H_{10}) = 0.5297 g

Molar Mass of diphenylacetylene (C_{14}H_{10}) = 178.21 g/mol

Then number of moles of diphenylacetylene (C_{14}H_{10})  = \frac{mass}{molar \ mass}

= \frac{0.5297  \ g }{178.24 \  g/mol}

= 0.002972 mol

By applying the law of calorimeter;

Heat liberated by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  = Heat absorbed by H_2O + Heat absorbed  by the calorimeter

Heat liberated  by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  =  msΔT + cΔT

= 1369 g  × 4.184 J g⁻¹°C⁻¹ × (26.05 - 22.95)°C + 916.9 J/°C (26.05 - 22.95)°C

= 17756.48 J + 2842.39 J

= 20598.87 J

Heat liberated by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  = 20598.87 J

Heat liberated by 1 mole of  diphenylacetylene (C_{14}H_{10}) will be = \frac{20598.87 \ J}{0.002972 \ mol}

= 6930979.139 J/mol

= 6930.98 kJ/mol

Since heat is liberated ; Then, the Molar heat of  Combustion  of  diphenylacetylene (C_{14}H_{10})  = -6.931 *10^3 \ kJ/mol

3 0
3 years ago
Read 2 more answers
I need help fast pls someone
Neko [114]

Answer:

I would say A. I'm no expert, but it can't be C obviously, and I think wind would hit all of it, wearing off the top as well like the great pyramids. B would be my next choice, but A i think would be best.

3 0
3 years ago
When a certain amount of MgF2 is added to water, the freezing point lowers by 3.5° C. What was the molality of the
Leni [432]

The molality of the solution is obtained as 0.63 m.

<h3>What is the freezing point?</h3>

The freezing point is the temperature at which the liquid is converted into solid.

We know that;

ΔT = 3.5° C

K = 1.86° C/m

i = 3

m = ?

Thus;

ΔT = K m i

m = ΔT/K i

m = 3.5° C/ 1.86° C/m * 3

m = 0.63 m

Learn more about freezing point:brainly.com/question/3121416

#SPJ1

6 0
2 years ago
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