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2 years ago

(Please help 25 points)

Physics

1 answer:

Maksim231197 [3]2 years ago

3 0

The potential energy (P.E) of X at r is less than P.E at s.

The total energy (T.E) of Y is less than total energy (T.E) of X.

The PE of Y at v is greater than the PE of Z at c.

The speed of Y at i is .greater than that at v.

The kinetic energy (KE) of z at u is less than that at n.

The PE of Y at s is less than the PE of X at c.

The PE of X at c is less than the PE of Z at c.

The potential energy (P.E) of X at r is less than P.E at s due to greater displacement at s.

The total energy (T.E) of Y is less than total energy (T.E) of X because X has greater displacement from the planet.

The PE of Y at v is greater than the PE of Z at c due to greater displacement at v.

<h3>Speed of Y at i is .... that at u</h3>

The speed of Y at i is .greater than that at v because i is closer to the planet than v.

The kinetic energy (KE) of z at u is less than that at n because n is closer to the planet and will have greater velocity.

The PE of Y at s is less than the PE of X at c, because position c has greater displacement.

The TE of Z is greater than the TE of X due to greater displacement of Z from the planet.

The PE of X at c is less than the PE of Z at c due to greater displacement of Z from c.

Learn more about potential energy here: brainly.com/question/1242059

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How do you know whether to put a nine or a 10 in front of the number on the weather station

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3 years ago

3. A sample of Gas is 25 € What will happen to its pressure when the temperature is increased to 50 €

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3 years ago

At a country music festival, a band is playing at the end of a crowded

Dominik [7]

Answer:

2270 full wavelengths.

Explanation:

The wavelength $\lambda$ of the sound wave (assuming sound speed of $v= 343m/s$ ) is

$\lambda = \dfrac{v}{f} = \dfrac{343m/s}{400hz}$

$\lambda = 0.8575m$ .

Now, assuming the distance to the last row is 1947m, the number $n$ of wavelengths that fit into this distance are

$n = \dfrac{1947m}{0.8575m}$

$n= 2270.55$

which is 2270 full wavelengths.

Hence, there are 2270 full wavelengths between the stage and the last row of the crowd.

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3 years ago

A record of travel along a straight path is as follows: 1. Start from rest with constant acceleration of 2.45 m/s^2 for 20.0 s.

Anton [14]

Answer:

a) The total displacement of the trip was 5.32 × 10³ m

b) The average speeds were:

leg 1: 24.5 m/s

leg 2: 49 m/s

leg 3: 23.9 m/s

Complete trip: 43.8 m/s

Explanation:

The position and velocity equations for an object moving along a straight line are as follows:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where

x = position at time t

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

v = velocity at time t

If the velocity is constant, then a = 0 and x = x0 + v · t where "v" is the velocity.

a) To calculate the total displacement of the trip, let´s calculate the distance traveled in each phase.

Phase 1:

x = x0 + v0 · t + 1/2 · a · t²

x = 0 m + 0 m/s · t + 1/2 · 2.45 m/s² · (20.0 s)²

x = 490 m

The velocity reached in that phase is:

v = v0 + a · t

v = 0 m/s + 2.45 m/s² · 20.0 s

v = 49.0 m/s

Phase 2:

x = x0 + v · t

x = 490 m + 49.0 m/s · 96.0 s

x = 5.19 × 10³ m

Phase 3:

x = x0 + v0 · t + 1/2 · a · t²

x = 5.19 × 10³ m + 49 m/s · 5.44 s - 1/2 · 9.00 m/s² · (5.44 s)²

x = 5.32 × 10³ m

The total displacement of the trip was 5.32 × 10³ m

b) The average speed is calculated as the traveled distance divided by the elapsed time:

average speed v = final position - initial position / (final time- initial time)

Phase 1:

v = 490 m - 0 m / 20.0 s = 24.5 m/s

Phase 2:

v = 5.19 × 10³ m - 490 / 96.0 s

v = 48.9 m/s (without rounding the final position the result is 49.0 m/s)

Phase 3:

v = 5.32 × 10³ m - 5.19 × 10³ m / 5.44 s = 23.9 m/s

For the complete trip:

v = 5.32 × 10³ m - 0 m / (20.0 s + 96.0 s + 5.44 s)

v = 43.8 m/s

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4 years ago