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ira [324]
3 years ago
9

What is the right answer. Thank you!!!! :) there is a picture also!

Mathematics
1 answer:
Archy [21]3 years ago
4 0
To solve this problem, you must know that an inscribed angle equals 1/2 of the arc that it intercepts.  

Therefore, because <ABC intercepts arc ADC, we know that

the measure of angle ABC = 1/2 * (measure of Arc ADC)

OR, when the values are substituted into the equation

165 = (1/2) (5)(x-3)

When simplified, this equation equals

330 = 5x - 15

345 = 5x

x = 69

Therefore, your answer is the second option, that x = 69 degrees.
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Evaluate the expression.
EastWind [94]

Answer:

42

Step-by-step explanation:

We use (BODMAS) :

Brackets

Order/Index

Division

Multiplication

Addition

Subtraction

Now we do bracket first :

7(3²) = 7(9) = 63

Now we do division :

63÷3 = 21

Now we do multiplication :

2 × 21 = 42

Hope this helped and have a good day

4 0
2 years ago
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levacccp [35]
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Pentagon PQRST and its reflection, pentagon P'Q'R'S'T', are shown in the coordinate plane below:
Ad libitum [116K]
<span>I have graphed the given coordinates of both pentagons. The reflection was across the y-axis where coordinates of Pentagon PQRST (-x,y) resulted to Pentagon P'Q'R'S'T' (x,y). The line of reflection between the pentagons was x = 0. Line of reflection is the midway between the pre-image and its reflection.</span>
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What is the constant rate of change of the graph below?
timofeeve [1]

Answer:

the constant rate of change is 20

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3 years ago
Gideon is painting all sides of a square pyramid-shaped decoration at the top of his fence post. A net of the decoration is show
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Area of the square = s^2 where s is the measure of the side
Area of the square = 4^2 = 16 in^2

Area of the triangle= 1/2 bh where b is the base of the triangle and h is height of the triangle
Area of the triangle = 1/2 (4) (5) = 10 in^2
We multiply the area of the triangle to four in order to obtain the total area of the triangles.
Total area of the triangles = 4 x 10 = 40 in^2

We then add the two areas,
Total Area = 16 + 40 = 56 in^2

Thus the total area that Gideon will have to paint for one square pyramid is 56 in^2.
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