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jenyasd209 [6]
1 year ago
5

Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. An

other bright star, Regulus , has a parallax of 0.042 arcseconds. What is its distance in parsecs
Physics
1 answer:
Vikentia [17]1 year ago
6 0

Answer: Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Another bright star, Regulus, has a parallax of 0.042 arcseconds. Then, the distance in parsecs will be,23.46.

Explanation: To find the answer, we have to know more about the relation between the distance in parsecs and the parallax.

<h3>What is the relation between the distance in parsecs and the parallax?</h3>
  • Let's consider a star in the sky, is d parsec distance from the earth, and which has some parallax of P amount.
  • Then, the equation connecting parallax and the distance in parsec can be written as,

                                     d=\frac{1}{P}

  • We can say that,

                                    dP=constant.\\thus,\\d_1P_1=d_2P_2

<h3>How to solve the problem?</h3>
  • We have given that,

                                     d_1=2.6 parsecs.\\P_1=0.379arcseconds.\\P_2=0.042 arcseconds.\\d_2=?

  • Thus, we can find the distance in parsecs as,

                                     d_2=\frac{d_1P_1}{P_2} =23.46 parsecs

Thus, we can conclude that, the distance in parsecs will be, 23.46.

Learn more about the relation connecting distance in parsecs and the parallax here: brainly.com/question/28044776

#SPJ4

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slava [35]

Answer:

option b

Explanation:

There is an object pulled inward in an electric field.

We have to find out of the four options given which is true.

a) The object has a neutral charge is false since when electric field pulls the object inward, there is a charge inside.

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c) The object has a negative charge will be correct only if the original charge was positive hence wrong

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Explanation:

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When a golf club hits a 0.0459 kg ball at rest, it exerts a 2380 N force for 0.00100 s. What is the speed of the ball afterwards
aksik [14]

Answer:

51.85m/s

Explanation:

Given parameters:

Mass of ball  = 0.0459kg

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   F = m x \frac{v - u}{t}  

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jek_recluse [69]

Answer:

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Explanation:

This is an exercise and kinematics, let's find the time it takes to reach the velocity  20 m / s

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          t = v / a

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as in this range it has a constant speed

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          x₂ = 20  25

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           x_total = 600 m

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