Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. An
1 answer:
Answer: Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Another bright star, Regulus, has a parallax of 0.042 arcseconds. Then, the distance in parsecs will be,23.46.
Explanation: To find the answer, we have to know more about the relation between the distance in parsecs and the parallax.
<h3>What is the relation between the distance in parsecs and the parallax?</h3>- Let's consider a star in the sky, is d parsec distance from the earth, and which has some parallax of P amount.
- Then, the equation connecting parallax and the distance in parsec can be written as,
- We can say that,
- We have given that,
- Thus, we can find the distance in parsecs as,
Thus, we can conclude that, the distance in parsecs will be, 23.46.
Learn more about the relation connecting distance in parsecs and the parallax here: brainly.com/question/28044776
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Answer:
Explanation:
A charge located at a point will experience a zero electrostatic force if the resultant electric field on it due to any other charge(s) is zero.
is located at the origin. The net force on it will only be zero if the resultant electric field intensity due to
and
at the origin is equal to zero. Therefore we can perform this solution without necessarily needing the value of
.
Let the electric field intensity due to be +
and that due to
be -
since the charge is negative. Hence at the origin;
From equation (1) above, we obtain the following;
From Coulomb's law the following relationship holds;
where is the distance of
from the origin,
is the distance of
from the origin and k is the electrostatic constant.
It therefore means that from equation (2) we can write the following;
k can cancel out from both side of equation (3), so that we finally obtain the following;
Given;
Substituting these values into equation (4); we obtain the following;