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Ludmilka [50]
3 years ago
9

A car drives for 30 km with a speed of 30m/s. How much time does it take the car to travel this distance?

Physics
1 answer:
Artist 52 [7]3 years ago
6 0

                   Time  =  (distance)  /  (speed)

                           =  (30 km)  /  (30 m/s)

                           =  (30,000 m)  /  (30 m/s)

                           =  (30,000 / 30)  sec

                           =      1,000 seconds

                           =      16 minutes  40 seconds  
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A small toy car travels 2.0 meters in 120 seconds. what is the speed of the car?
mamaluj [8]

Answer:\dfrac{1}{60} ms^{-1}

Explanation:

Speed of an object is defined as the ratio of the distance covered by the object to the time taken to cover that distance.

Let s be the speed of the object.

Let D be the distance travelled by the object.

Let t be the time taken by the object.

So,s=\frac{D}{t}

s=\frac{2}{120}=\frac{1}{60}ms^{-1}

So,the speed of the car is \frac{1}{60}ms^{-1}

4 0
3 years ago
Muscles use force to move objects. When using a ramp to do work, would your muscles use more force or less force?
White raven [17]
Less because the ramp is letting off force but i does depend on the way you are going on the ramp

7 0
2 years ago
Read 2 more answers
If the work done to stretch an ideal spring by 4.0 cm is 6.0 j, what is the spring constant (force constant) of this spring?
Alisiya [41]

Answer:

The spring constant is 3750 N/m  

Explanation:

Use the following two relationships:

(Work) = (Force) x (Displacement)

(Force) = (Spring constant) x (Displacement)

=>

(Spring constant) = (Force) / (Displacement) = (Work) / (Displacement)^2

(Spring constant) = 6.0 kg.(m^2/s^2) / 0.0016 m^2 = 3750 N/m

The spring constant is 3750 N/m  

4 0
3 years ago
A student took a calibrated 250.0 gram mass, weighed it on a laboratory balance, and found it read 266.5 g. What was the student
Kruka [31]

Answer:

B. 6.6%

Explanation:

The percentage error of a measurement can be calculated using the formula;

Percent error = (experimental value - accepted value / accepted value) × 100

In this question, the calibrated 250.0 gram mass is the accepted value while the weighed mass of 266.5 g is the experimental or measured value.

Hence, the percentage error can be calculated thus;

Percent error = (266.5-250.0/250.0) × 100

Percent error = 16.5/250 × 100

Percent error = 0.066 × 100

Percent error = 6.6%

7 0
3 years ago
.A hard rubber ball, released at chest height, falls to the pavement and bounces back to nearly the same height. When it is in c
ohaa [14]

Answer:

 a = 1.1 10⁵ m / s²

Explanation:

This is a momentum exercise, where we use the relationship between momentum and momentum

          I = ∫ F dt = Δp

= p_f - p₀

as they indicate that the ball bounces at the same height, we can assume that the moment when it reaches the ground is equal to the moment when it bounces, but in the opposite direction

        F t = 2 (m v)

therefore the average force is

         F = 2 m v / t

where in general the mass of the ball unknown, the velocity of the ball can be calculated using the conservation of energy

starting point. Done the ball is released with zero initial velocity

        Em₀ = U = mgh

final point. Upon reaching the ground, just before the deformation begins

        Em_f = K = ½ m v²

energy is conserved in this system

        Em₀ = Em_f

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        v = √ (2gh)

This is the velocity of the body when it reaches the ground, so the force remains

        F = 2m √(2gh)   /t

where the height of the person's chest is known and the time that the impact with the floor lasts must be estimated in general is of the order of milli seconds

knowing this force let's use Newton's second law

          F = m a

          a = F / m

 

          a = 2 √(2gh) / t

We can estimate the order of magnitude of this acceleration, assuming the person's chest height of h = 1.5 m and a collision time of t = 1 10⁻³ s

         a = 2 √ (2 9.8 1.5) / 10⁻³

         a = 1.1 10⁵ m / s²

6 0
2 years ago
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