<u>Answer:</u> 2.00 atm
<u>Explanation:</u>
The gas is kept under the same temperature in this problem. Assuming the amount of gas is constant, we can apply the Boyle's law.
The Boyle's law equation,
P₁V₁ = P₂V ₂
Plug in the values,
1.00 atm x 4.0 L = P₂ x 2.0 L
Simplify,
4.00 atm L = 2 P₂ L
Now flip the equation,
2 P₂ L = 4.00 atm L
Dividing both sides by 2 we get,
P₂ = 2.00 atm
Answer:
Molarity is 0.04M
Explanation:
First of all, let's determinate the moles of aspirin in that sample
Mass / Molar mass = Moles
360 mg = 0.360 g
0.360 g / 180 g/m = 0.002 moles
This moles that are included in 200 mL of solution, are also in 50 mL.
So molarity is mol/L
50 mL = 0.05 L
0.002 m / 0.05 L = 0.04M
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<h3>Answer = 2</h3>
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<h3>Known</h3>
Mass = 32grams
Name of atom = Methane (CH4)
Molar mass C = 12
Molar mass H = 1
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<h3>Question</h3>
molecules (mol?)
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<h3>Way to do</h3>
mass = mol × molar mass
32g = mol × (CH4)
33g = mol × (12 + (4×1))
32g = mol × 16
mol = 32 : 16
mol = 2
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#Ey tell me if its mol or total particles
1) Endothermic
2) Heat absorbed by reaction = 2511.6J
3)ΔH_rxn = 18.2 kJ/ mol
Explanation:
Mass of KCl = 10.3 g
Moles of KCl = mass of KCl / molar mass of KCl
= 10.3 g / 74.5513 g/mol
=0.138 mol
Mass of water, m = 200 g
Specific heat of water, C= 4.186 Jg^-1°C^-1
T_initial = 22.0C
T_final = 19.0°C
ΔT = T_final - T_initial
=19.0°C - 22.0°C
= -3.0°C
Heat absorbed = Heat released
q_rxn =-q_water
so,
q_water = m CΔT
substitute
q_water = 200g * 4.186J g^-1 °C^-1 *(-3.0°C)
= -2511.6J
Heat absorbed by reaction = 2511.6J
q_rxn = -q_water = 2511.6J
ΔH_rxn = q_rxn /moles of KCl
=2511.6J / 0.138 mol
ΔH_rxn =18.2kJ / mol
The reaction is a endothermic reaction.