Answer:
F - M a force exerted by scales on student
M a = M (9.8 + 4.9) m/s^2 upwards chosen as positive
a = 1.5 g net acceleration of student due to force of scales
W =M g weight of student (actual weight)
Wapp = M 1.5 * g apparent weight (on scales) of student
The benefits of the cool down period are quite important, it allows your body to slow your heart rate at a nice healthy safe pace, if you stop right away it can cause breathing, heart, and muscle problems.
Answer:
![T=66262.4s](https://tex.z-dn.net/?f=T%3D66262.4s)
Explanation:
From the question we are told that:
Altitude ![A=2.90 *10^7](https://tex.z-dn.net/?f=A%3D2.90%20%2A10%5E7)
Mass ![m=5.97 * 10^{24} kg](https://tex.z-dn.net/?f=m%3D5.97%20%2A%2010%5E%7B24%7D%20kg)
Radius ![r=6.38 *10^6 m.](https://tex.z-dn.net/?f=r%3D6.38%20%2A10%5E6%20m.)
Generally the equation for Satellite Speed is mathematically given by
![V=(\frac{GM}{d} )^{0.5}](https://tex.z-dn.net/?f=V%3D%28%5Cfrac%7BGM%7D%7Bd%7D%20%29%5E%7B0.5%7D)
![V=(\frac{6.67*10^{-11}*5.97 * 10^{24}}{6.38 *10^6+2.90 *10^7} )^{0.5}](https://tex.z-dn.net/?f=V%3D%28%5Cfrac%7B6.67%2A10%5E%7B-11%7D%2A5.97%20%2A%2010%5E%7B24%7D%7D%7B6.38%20%2A10%5E6%2B2.90%20%2A10%5E7%7D%20%29%5E%7B0.5%7D)
![V=3354.83m/s](https://tex.z-dn.net/?f=V%3D3354.83m%2Fs)
Therefore
Period T is Given as
![T=\frac{2 \pi *a}{V}](https://tex.z-dn.net/?f=T%3D%5Cfrac%7B2%20%5Cpi%20%2Aa%7D%7BV%7D)
![T=\frac{2 \pi *(6.38 *10^6+2.90 *10^7}{3354.83}](https://tex.z-dn.net/?f=T%3D%5Cfrac%7B2%20%5Cpi%20%2A%286.38%20%2A10%5E6%2B2.90%20%2A10%5E7%7D%7B3354.83%7D)
![T=66262.4s](https://tex.z-dn.net/?f=T%3D66262.4s)
I think the answer may be the letter B
The area-
The area under the line in a velocity-time graph represents the distance travelled. To find the distance travelled in the graph above, we need to find the area of the light-blue triangle and the dark-blue rectangle.
<span><span>Area of light-blue triangle -
<span>The width of the triangle is 4 seconds and the height is 8 meters per second. To find the area, you use the equation: <span>area of triangle = 1⁄2 × base × height </span><span>so the area of the light-blue triangle is 1⁄2 × 8 × 4 = 16m. </span></span></span><span> Area of dark-blue rectangle
The width of the rectangle is 6 seconds and the height is 8 meters per second. So the area is 8 × 6 = 48m.</span><span> Area under the whole graph
<span>The area of the light-blue triangle plus the area of the dark-blue rectangle is:16 + 48 = 64m.<span>This is the total area under the distance-time graph. This area represents the distance covered.</span></span></span></span>