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tigry1 [53]
3 years ago
10

The acceleration of a baseball after it is hit by a bat depends on the mass of the ball and the net force on the

Physics
1 answer:
Scrat [10]3 years ago
7 0

Answer:

B. Newton's second law of motion

Explanation:

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

Net \; Force = mass * acceleration

Making acceleration the subject of formula, we have;

Acceleration = \frac {Net \; Force}{Mass}

In this scenario, the acceleration of a baseball after it is hit by a bat depends on the mass of the ball and the net force on the ball. Thus, this example best illustrates Newton's second law of motion.

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When a liquid is cooled, the kinetic energy of the particles . The force of attraction between the particles , the space between
anzhelika [568]

Answer:

For the first blank, the answer is decreases. For the second blank, the answer is increases. And finally for the third blank, the answer is decreases.

Explanation:

For the first blank, the answer is decreases. For the second blank, the answer is increases. And finally for the third blank, the answer is decreases.

When a liquid is cooled, the kinetic energy of the particles decreases. The force of attraction between the particles increases, the space between the particles decreases, and the matter changes its state to solid.

4 0
3 years ago
Read 2 more answers
If earth stops rotating then what will be the value of 'g' at poles
Marianna [84]
The value of 'g' is not affected by rotation at any place on Earth.
7 0
3 years ago
A life preserver is thrown from an helicopter straight down to a person in distress. The initial velocity of the life preserver
Leno4ka [110]

Answer:29.627 m

Explanation:

Given

Initial velocity of life preserver(u) is 1.6 m/s

it takes 2.3 s to reach the water

using equation of motion

v=u+at

v=1.6+9.81\times 2.3

v=24.163 m/s

Let s be the height of life preserver

v^2-u^2=2gs

24.163^2-1.6^2=2\times 9.81\times s

s=\frac{581.29}{2\times 9.81}

s=29.627 m

6 0
3 years ago
A bicyclist is travelling at 25 m/s when he begins to decelerate at -4m/s2 . How fast is travelling after 5 seconds
Umnica [9.8K]

Initial velocity (Vi) = 25 m/s

acceleration (a) = -4 m/s^{2}

time interval (t) = 5 sec

let us assume that final velocity after 5 sec be Vf

As acceleration is constant, we can apply the the equation of motion with constant acceleration i.e. V_{f} = V_{i} + at

Hence, V_{f} = 25 +(-4)(5) = 25 -20 = 5 m/s

so, the velocity of bicyclist will be 5 m/s after 5 sec

7 0
3 years ago
What displacement in cm would occur with a 75 N/m spring if you placed a 300 N weight on the spring?
ollegr [7]

Surface tension=75N/m

Weight=300N

\\ \bull\tt\longmapsto Surface\:Tension=\dfrac{Weight}{Displacement}

\\ \bull\tt\longmapsto Displacement=\dfrac{Weight}{Surface\:Tension}

\\ \bull\tt\longmapsto Displacement=\dfrac{300}{75}

\\ \bull\tt\longmapsto Displacement=4m

\\ \bull\tt\longmapsto Displacement=400cm

6 0
3 years ago
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