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klio [65]
2 years ago
6

A box with a mass of 2 kg only has four forces acting on it: One force of 16 N due East. One force of 24 N due South. One force

of 16 N due West. One force of 18 N due North. What is the magnitude of the box's acceleration, in m/s2
Physics
2 answers:
katrin [286]2 years ago
7 0

Answer:

The acceleration of the object is 3 m/s2.

Explanation:

  • The force on the object is acting along the four directions which are perpendicular to each other.
  • Since the north and south directions are opposite to each other, the magnitude of the net force along north-south direction is (24-18)=6 N.
  • Since the east and west directions are opposite to each other, the magnitude of the net force along east-west direction is (16-16)=0 N.
  • Therefore the magnitude of the net force on the object is 6 N
  • By Newton's second law, the force F on the object is given by the formula F=ma.
  • Here m= 2kg, therefore 6 =(2)a which gives a = 3 m/s2.        

Learn more about Newton's law.

brainly.com/question/13447525

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julsineya [31]2 years ago
3 0

Answer:

The magnitude of acceleration is 3 m/s^2.

Explanation:

The net force along North-South direction is 18-24=-6 N.

The net force along East-West direction is 16-16=0 N

The net magnitude of force is square root of (-6)^2+0^2 which is 6 N.

By Newton's Second law,

Force F=ma

Therefore acceleration a=F/m

                                       a=6/2

                                       a=3 m/s^2

Learn more about Newton's second law.

brainly.com/question/13447525

#SPJ10

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a 75 kg man is standing at rest on ice while holding a 4kg ball. if the man throws the ball at a velocity of 3.50 m/s forward, w
AysviL [449]

Answer:

His resulting velocity will be 0.187 m/s backwards.

Explanation:

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Mass of the man is, M=75\ kg

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Initial velocity of the man is, u_m=0\ m/s(rest)

Initial velocity of the ball is, u_b=0\ m/s(rest)

Final velocity of the ball is, v_b=3.50\ m/s

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In order to solve this problem, we apply law of conservation of momentum.

It states that sum of initial momentum is equal to the sum of final momentum.

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Initial momentum = Initial momentum of man and ball

Initial momentum = Mu_m+mu_b=75\times 0+4\times 0 =0\ Nm

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Final momentum = Mv_m+mv_b=75\times v_m+4\times 3.50 =75v_m+14

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