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klio [65]
2 years ago
6

A box with a mass of 2 kg only has four forces acting on it: One force of 16 N due East. One force of 24 N due South. One force

of 16 N due West. One force of 18 N due North. What is the magnitude of the box's acceleration, in m/s2
Physics
2 answers:
katrin [286]2 years ago
7 0

Answer:

The acceleration of the object is 3 m/s2.

Explanation:

  • The force on the object is acting along the four directions which are perpendicular to each other.
  • Since the north and south directions are opposite to each other, the magnitude of the net force along north-south direction is (24-18)=6 N.
  • Since the east and west directions are opposite to each other, the magnitude of the net force along east-west direction is (16-16)=0 N.
  • Therefore the magnitude of the net force on the object is 6 N
  • By Newton's second law, the force F on the object is given by the formula F=ma.
  • Here m= 2kg, therefore 6 =(2)a which gives a = 3 m/s2.        

Learn more about Newton's law.

brainly.com/question/13447525

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julsineya [31]2 years ago
3 0

Answer:

The magnitude of acceleration is 3 m/s^2.

Explanation:

The net force along North-South direction is 18-24=-6 N.

The net force along East-West direction is 16-16=0 N

The net magnitude of force is square root of (-6)^2+0^2 which is 6 N.

By Newton's Second law,

Force F=ma

Therefore acceleration a=F/m

                                       a=6/2

                                       a=3 m/s^2

Learn more about Newton's second law.

brainly.com/question/13447525

#SPJ10

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AnnyKZ [126]
In physical chemistry or in thermodynamics, the work done on the system or by the system (depending on the sign convention) can be determined in several ways. When assumptions like ideal gas behavior is applied, then the formula for work is

W = Δ(PV)

which is the change of the product of Pressure and Volume. But since it was specified that Pressure is constant, the work could be simplified into

W = PΔV = P(V₂ - V₁)

Since we already know the constant pressure and the volumes of the ideal gas before and after the change, we could now solve for work. But let's establish first the units of work which is in Joules. When simplified, Joules is equal to m³*Pa. So, we first change the unit of pressure from atm to Pascals ( 1 atm = 101,325 Pa) and the unit of volume from liters to m³ (1 m³ = 1000 L),

1.5 atm * 101325 Pa/1 atm = 151987.5 Pa
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3 years ago
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A battery charges a parallel-plate capacitor fully and then is removed. The plates are then slowly pulled apart. What happens to
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Answer:

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Explanation:

from the relation E= \frac{V}{d}

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            d= distance

Hence the voltage is going to be V= E×d.

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A hollow metal sphere has 7cm and 11cm inner and outer radii, respectively. The surface charge density on the inside surface is
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Answer:

A) and B) the electric  field is 0

C) E = - 28266.88 [N/C]

D) The electric field is inward the sphere

E) E = 18463,47 [N/C]

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Explanation:

A) At point 4 cm from the center, strength of the electric field is 0.

If we imagine a gaussian sphere of radius 4 it wont enclose any net charge

B) There is not electric field at radius r = 4 cm

C) We first compute the whole charge in the surface of the sphere of radius r = 7 cm

A = 4π* r²    ⇒ A = 4* 3,14 * ( 0,07 m)²     ⇒ A = 0.615 m²

And total charge of the inside sphere is

Q = -300 * 10⁻⁹ * 0.615  [C]   ⇒  Q = - 18,46 *10⁻⁹ [C]

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E = - K * 18.46* 10⁻⁹ [C]/ (0.08)² m²      ⇒ E = - K * 2884.38*10⁻⁹ [C/m²]

K = 9.8 *10⁹ [Nm²/C² ]       and      E = - 9.8* 2884.38 [N/C]

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D) The negative sign indicates that the electric field is inward

E) We need to compute total charge in the outside surface of the bigger shell

Q = 300*10⁻⁹ [C]   and the area of the shell is

A = 4*π * (0.11)² m²       ⇒ A  = 0, 1519m²

Q₂ = 300 * 10⁻⁹ * 0,1519    [C]      Q₂ = 45,59 * 10⁻⁹ [C]

The net charge enclosed for a gaussian surface passing through point at 12 cm from the center is:

Q₂ - Q  =  + 45.59* 10⁻⁹  - 18.46 * 10⁻⁹     Q(t) = 27,13* 10⁻⁹ [C]

and the strength of the electric field in that point is

E =  K * 27,13* 10⁻⁹ / (0,12)²      E  = 9.8 *27,13/ 0,0144 [N/C]

E = 18463,47 [N/C]

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A light wave moves from a medium where particles of matter are closely packed to a medium made of very little matter. How do you
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Answer:

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Explanation:

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v= ω r

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ω=Angular speed

r=radius

The total kinetic energy KE

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Moment of inertia of solid sphere I

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Now from energy conservation

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Potential energy at bottom = 0

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Kinetic energy at bottom = KE

m g h + 0 = 0 + KE

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KE= 30 J

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