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jok3333 [9.3K]
2 years ago
15

The second order reaction A → Products takes 13.5 s for the concentration of A to decrease from 0.740 M to 0.319 M. What is the

value of k for this reaction?
Chemistry
1 answer:
Ivanshal [37]2 years ago
8 0

The rate constant of the second order reaction is 0.137 M-1s-1.

<h3>What is the rate constant?</h3>

For the second order reaction we can write;

1/[A] = kt + 1/[A]o

[A]o = initial concentration

[A] = final concentration

k = rate constant

t = time

Now;

1/0.319 = 13.5k + 1/ 0.740

1/0.319 - 1/0.740 = 13.5k

3.13 - 1.35 = 13k

k = 3.13 - 1.35/13

k = 0.137 M-1s-1

Learn more about second order reaction:brainly.com/question/12446045

#SPJ1

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Which term describes energy stored in the bonds between atoms?
horsena [70]

Answer:

B.) Chemical

Explanation:

The energy stored in the bonds between atoms is referred to as chemical energy. I hope this helps! ^-^

8 0
2 years ago
Express the frequency in inverse seconds. n=5--&gt;n=1
Natalija [7]

The frequencies expressed in inverse seconds are 5 s⁻¹  and 1 s⁻¹.

<h3>What is frequency?</h3>

Frequency is the number of complete cycles in a second made by a wave.

F = 1/T

F = n/t

<h3>When n = 5</h3>

F = 5/s =  5 s⁻¹ = 5Hz

<h3>When n = 1</h3>

F = 1/s =  1 s⁻¹ = 1Hz

Learn more about frequency here: brainly.com/question/254161

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4 0
2 years ago
What are the physical properties of toothpaste
bogdanovich [222]
The whitening toothpastes showed differences in their physical-chemical properties. All toothpastes promoted changes to the surface, probably by the use of a bleaching agent.
5 0
3 years ago
At 7 degrees Celsius the volume of gas is 49 liters. At the same pressure its volume is 74 mL at what temperature
Romashka-Z-Leto [24]
Charle's law gives the relationship between volume and temperature of gas.
It states that at constant pressure, volume of gas is directly proportional to temperature of gas.
V/T = k
where V - volume , T - temperature and k- constant 
\frac{V1}{T1} =  \frac{V2}{T2}
parameters for the first instance are on the left side of the equation and parameters for the second instance are on the right side of the equation 
T1 - 7 °C + 273 = 280 K
substituting these values in the equation 
\frac{49 mL}{280K} =  \frac{74 mL}{T}
T = 423 K
temperature in Celcius scale - 423 K - 273 = 150 °C
4 0
3 years ago
Some oxides are given below. (i)Na2O (ii)NO2 (iii) CO2 (iv) MgO a) Which are the basic oxides among these? b) What is the name o
umka2103 [35]
<h3>Further explanation</h3>

Basic oxides ⇒ metal(usually alkali/alkaline earth) +O₂

L + O₂ ⇒ L₂O

L + O₂ ⇒ LO

Dissolve in water becomes = basic solution

L₂O+H₂O⇒ 2LOH

LO + H₂O⇒ L(OH)₂

So the basic oxides : Na₂O and MgO

Na₂O + H₂O⇒NaOH

MgO +H₂O⇒Mg(OH)₂

The aqueous solution of CO₂(dissolve in water)

CO₂ + +H₂O⇒ H₂CO₃(carbonic acid)

5 0
3 years ago
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