Answer:
10mm
Explanation:
According to Hooke's law which states that "the extension of an elastic material is directly proportional to the applied force provided the elastic limit is not exceeded. Direct proportionality there means, increase/decrease in the force leads to increase/decrease in extension.
Mathematically, F = ke where;
F is the applied force
k is the elastic constant
e is the extension
from the formula k = F/e
k = F1/e1 = F2/e2
Given force of 1N indents the spring inwards by 2mm, this means force of 1N generates extension of 2mm
Let F1 = 1N e1 = 2mm
The extension that will be produced If force of 5N is applied to the string is what we are looking for. Therefore F2 = 5N; e2= ?
Substituting this values in the formula above we have
1/2=5/e2
Cross multiplying;
e2 = 10mm
This shows that we must have dent it by 10mm before it pushes outwards by a 5N force
Rock fragments that are cemented together and compacted over time turn into sedimentary rock.
the whole process can be summed up as the combination of weathering of rocks to form sediments, transport of the sediments to form deposits, cementation of deposits to forms the sedimentary rocks.
Answer:
a)
two like charges always repel each other while two unlike charges attract each other. Since the spring stretches by 0.039 m, the charges have the same sign. both charges are positive(+) or Negative (-)
b)
both q1 and q1 are 8.35 × 10⁻⁶ C or -8.35 × 10⁻⁶ C
Explanation:
Given that;
L = 0.26 m
k = 180 N/m
x = 0.039 m
a)
we know that two like charges always repel each other while two unlike charges attract each other. Since the spring stretches by 0.039 m, the charges have the same sign.
b)
Spring force F = kx
F = 180 × 0.039
F = 7.02 N
Now, Electrostatic force F = Keq²/r²
where r = L + x = ( 0.26 + 0.039 )
we know that proportionality constant in electrostatics equations Ke = 9×10⁹ kg⋅m3⋅s−2⋅C−2
so from the equation; F = Keq²/r²
Fr² = Keq²
q = √ ( Fr² / Ke )
we substitute
q = √ ( 7.02 N × ( 0.26 + 0.039 )² / 9×10⁹ )
q = √ ( 7.02 N × ( 0.26 + 0.039 )² / 9×10⁹ )
q = √ (0.627595 / 9×10⁹)
q = √(6.97 × 10⁻¹¹)
q = 8.35 × 10⁻⁶ C
Therefore both q1 and q1 are 8.35 × 10⁻⁶ C or -8.35 × 10⁻⁶ C
<span>the emission of energy as electromagnetic waves or as moving subatomic particles, especially high-energy particles that cause ionization.</span>
With the information given, one can presume that:
Work = F • d (so W = 875,000 J)
The equation for power is:
P = W/t (so P = 19444.4 Watts)
1 Watt = 1000 Kilowatts
So the answer would be 19,444,444 kW