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3 years ago

Describe the possible long term impact of a catastrophic event

1 answer:

4 0

However, the Northridge earthquake itself, a significant catastrophic event<span>, had ... prices, reflecting their increased </span>potential<span> for physical destruction. ... local neighborhoods and find no </span>long-term impact<span> on home values, resident incomes or occupancy rates. ... We briefly </span>describe<span> the variety of data sources used in the paper.</span>

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Answer all these questions for a TON OF POINTS

IgorC [24]

1). E
2). A
3). 4N
4). D

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3 years ago

Read 2 more answers

A person is placed in a large, hollow, metallic sphere that is insulated from ground. (a) If a large charge is placed on the sph

stiv31 [10]

Answer:

Explanation:

It is given that the sphere is insulated from ground and a large charge is placed on the sphere. The charge on the hollow sphere will always remain on the outer surface of the sphere and there will be no charge on the inner surface of the sphere.

If a person touches the inner surface of the sphere then he will not be harmed as there is no charge on the inner surface of the sphere.

If a person carries the charge of the opposite sign of the same magnitude then the sphere and person get neutralized upon touching the sphere.

If a person does not touches the sphere then the charge on the outer surface will be zero and there will be a positive charge on the inner surface of the sphere

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3 years ago

PLEASE ASAP ILL GIVE BRAINLIEST.

Fiesta28 [93]

Acceleration no longer exist as the car stops.

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3 years ago

A thin ring of radius 73 cm carries a positive charge of 610 nC uniformly distributed over it. A point charge q is placed at the

kow [346]

Answer:

q = - 93.334 nC

Explanation:

GIVEN DATA:

Radius of ring 73 cm

charge on ring 610 nC

ELECTRIC FIELD p FROM CENTRE IS AT 70 CM

E = 2000 N/C

Electric field due tor ring is guiven as

$E = \frac{KQx}{[x^2+ R^2]^{3/2}}$

$E = \frac{9\time 10^9 \times 610\times 10^[-9} 0.70}{(0.70^2 + 0.73^2)^{3/2}}$

E1 = 3714.672 N/C

electric field due to point charge q

$E =\frac[kq}{x^2}$

$E = \frac{9\times 10^9 \times q}{0.70^2}$

$E2 = 1.837\times 10^{10}\times q$

now the eelctric charge at point P is

E = E1 + E2 $2000 = 3714.672 + 1.837\times 10[10} \times q$

solving for q

q = - 93.334 nC

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3 years ago

In the first direct detection of gravitational waves by LIGO in 2015, the waves came from A. the collapse of a nearby star into

diamong [38]

In the first direct detection of gravitational waves by LIGO in 2015, the waves came from the merger of two black holes. Option B is correct. This is further explained below.

<h3>What are gravitational waves?</h3>

A gravitational wave is simply defined as a ripple in space that is unseen though extremely rapid. Gravitational waves move at light speed. As they pass past, these waves compress and stretch everything in their path.

In conclusion, the merger of two black holes is the first direct detection of gravitational waves.