Why is AU (astronomical unit) the unit of distance that we used instead of kilometers?
1 answer:
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Answer:
28 m/s^2
Explanation:
distance, s = 14 m
time, t = 2 - 1 = 1 s
initial velocity, u = 0 m/s
Let a be the acceleration.
Use third equation of motion
a = 28 m/s^2
Thus, the acceleration is 28 m/s^2.
Answer
given,
mass of the shell = 87 g = 0.087 Kg
speed of the muzzle = 853 m/s
mass of the helicopter = 4410 kg
A burst of 176 shell fired in 2.93 s
resulting average force = ?
momentum of the shell = m v
= 0.087 x 853
= 74.21 kgm/s
momentum of 176 shell is = 176 p
= 176 x 74.21
= 13060.96
momentum of helicopter = - 13060.96 kgm/s
amount of speed reduce a =
a=
a = 2.96 m/s²
velocity = \dfrac{2.96}{2.93}
v = 1.01 m/s
1.602177e-15 joules are in 10,000 electron volts
You must throw the snow ball by velocity 9.43 m/s horizontally to
hit him
Explanation:
You throw the snow ball horizontally from a height 5.5 meters
Your favorite physics teacher is 10 m away from you
You hit him on the foot
1. The initial velocity of the ball is v
2. The vertical component of v is zero because you throw the ball
horizontally
3. The vertical distance h is 5.5 m
4. The horizontal distance x is 10 m
We need to find how fast you must throw the snow ball to hit him
→ h = t +
g t²
→ h = -5.5 m ⇒ height below the point of thrown
→ g = -9.8 m/s²
→ = 0 ⇒ vertical component of v
→ -5.5 = (0) t + (-9.8) t²
→ - 5.5 = -4.9 t²
Divide both sides by -4.9
→ t² = 1.12245
Take √ for both sides
→ t = 1.06 seconds
→ x = t
→ = v
→ x = 10 m , t = 1.06
→ 10 = v(1.06)
Divide both sides by 1.06
→ v = 9.43 m/s
You must throw the snow ball by velocity 9.43 m/s horizontally to
hit him
Learn more:
You can learn more about velocity in brainly.com/question/13103128
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