A spring with a constant k=400n/m shoots a 1. 00kg ball up a frictionless incline after being compressed 0. 150m. what is the ma
1 answer:
The maximum height reached by the ball is 0.46m.
To find the answer, we have to know about the potential energy of a spring mass system.
<h3>How to find the maximum height reached by the ball?</h3>- It is given that,
- We have to find the maximum height reached by the ball.
- Thus, we have the expression for potential energy of a spring mass system and that of gravitational field as,
- Combining both, we get,
Thus, we can conclude that, the maximum height reached by the ball is 0.46m.
Learn more about the potential energy here:
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Answer:
V = 4.81 V
Explanation:
- As the potential difference between the battery terminals, is less than the rated value of the battery, this means that there is some loss in the internal resistance of the battery.
- We can calculate this loss, applying Ohm's law to the internal resistance, as follows:
- The value of the potential difference between the terminals of the battery, is just the voltage of the battery, minus the loss in the internal resistance, as follows:
- We can solve for rint, as follows:
- When the circuit draws from battery a current I of 0.469A, we can find the potential difference between the terminals of the battery, as follows:
- As the current draw is larger, the loss in the internal resistance will be larger too, so the potential difference between the terminals of the battery will be lower.