A spring with a constant k=400n/m shoots a 1. 00kg ball up a frictionless incline after being compressed 0. 150m. what is the ma

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5 months ago

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ximum height reached by the ball?

1 answer:

Zielflug [23.3K] · Answer 1 · 2024-09-18T11:53:34+03:00

The maximum height reached by the ball is 0.46m.

To find the answer, we have to know about the potential energy of a spring mass system.

<h3>How to find the maximum height reached by the ball?</h3>

$k=400N/m\\m=1kg\\x=0.150m\\h=?\\$

We have to find the maximum height reached by the ball.
Thus, we have the expression for potential energy of a spring mass system and that of gravitational field as,

$U=\frac{1}{2}kx^2 \\U=mgh$

$h=\frac{kx^2}{2mg} =\frac{400*(0.15)^2}{2*1*9.8} =0.46m$

Thus, we can conclude that, the maximum height reached by the ball is 0.46m.

Learn more about the potential energy here:

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