To throw an object into the space you need to throw it with the escape velocity of the earth which is 11.2 km/sec. therefore if you can throw an object with the speed of 11.2 km/sec it will leave the earth atmosphere and will reach to the space.
Answer:
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Acceleration = change in velocity/ time = (final velocity - initial velocity)/time
<span>accel = (60ft/s - 45ft/s)/5s = 3 ft/s</span>
Answer:
2 kg
Explanation:
Assuming the rod's mass is uniformly distributed, the center of mass is at half the length.
Sum of the moments at the balance point:
-(Mg)(L/3) + (mg)(L/2 − L/3) = 0
(Mg)(L/3) = (mg)(L/2 − L/3)
(Mg)(L/3) = (mg)(L/6)
2M = m
M = 1 kg, so m = 2 kg.
The mass of the rod is 2 kg.
Answer:
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Explanation: