Answer:
The pressure difference is 25.8kPa while the force exerted on the window by air pressure is 3.02 kN
Explanation:
Using the Bernoulli's equation
Here
- Pin-Pout is the pressure difference which is to be calculated.
- ρ is the density of air whose value is 1.29 kg/m^3
- vin is the velocity of air inside which is 0 m/s
- vout is the velocity of air outside which is 200 m/s
Substituting values in the above equation yields
So the pressure difference is 25.8kPa.
As force is given by
Here
- ΔP is the pressure difference calculated above
- A is the area of the window given as
Now force is
So the force exerted on the window by air pressure is 3.02 kN
Use the formular d = v x t
d = 2m
v= 100m/s
t= d / v
= 2 / 100
= 0.02sec
Answer:
A. Both spheres land at the same time.
Explanation:
The horizontal motion doesn't affect the vertical motion. Since the two spheres have the same initial vertical velocity and same initial height, they land at the same time.