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Scorpion4ik [409]
2 years ago
5

How much force would you need to accelerate a 4 kg object from a standstill to 5 m/s2?

Physics
1 answer:
djyliett [7]2 years ago
3 0

To solve this, we use Newtons 2nd law of motion which states that F = m⋅a . This means that a force F is required to make a body of mass m accelerate with an acceleration of a . So if a body of 4kg is to be accelerated by a force 17N then its acceleration can be found by putting into the formula F = m⋅a .

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Air enters a turbine operating at steady state at 8 bar, 1400 K and expands to 0.8 bar. The turbine is well insulated, and kinet
vladimir2022 [97]

To solve this problem it is necessary to apply the concepts related to the adiabatic process that relate the temperature and pressure variables

Mathematically this can be determined as

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

Where

T_1 =Temperature at inlet of turbine

T_2 = Temperature at exit of turbine

P_1 = Pressure at exit of turbine

P_2 =Pressure at exit of turbine

The steady flow Energy equation for an open system is given as follows:

m_i = m_0 = m

m(h_i+\frac{V_i^2}{2}+gZ_i)+Q = m(h_0+\frac{V_0^2}{2}+gZ_0)+W

Where,

m = mass

m_i = mass at inlet

m_0= Mass at outlet

h_i = Enthalpy at inlet

h_0 = Enthalpy at outlet

W = Work done

Q = Heat transferred

V_i = Velocity at inlet

V_0= Velocity at outlet

Z_i= Height at inlet

Z_0= Height at outlet

For the insulated system with neglecting kinetic and potential energy effects

h_i = h_0 + W

W = h_i -h_0

Using the relation T-P we can find the final temperature:

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

\frac{T_2}{1400K} = (\frac{0.8bar}{8nar})^{(\frac{1.4-1}{1.4})}

T_2 = 725.126K

From this point we can find the work done using the value of the specific heat of the air that is 1,005kJ / kgK

So:

W = h_i -h_0

W = C_p (T_1-T_2)

W = 1.005(1400-725.126)

W = 678.248kJ/Kg

Therefore the maximum theoretical work that could be developed by the turbine is 678.248kJ/kg

5 0
3 years ago
The distance between your and your is displacement
Kay [80]
The distance between your initial position and your final position is displacement. Often denoted by x or Δx
4 0
3 years ago
rt A For a given substance, do you expect the density of the substance in its liquid state to be closer to the density in the ga
Nat2105 [25]

Answer:

A substance in its liquid state is closer to the density of its solid phase than the density of its gaseous phase.

Explanation:

For a substance in its liquid state we can expect the density of the substance more closer to the density of its solid state than its gaseous state because the the inter-molecular space is much close near to incompressible in the liquid state and the the inter-molecular force of attraction is much higher as compared to gaseous state.

In contrast to the molecular properties in liquid state gases have almost negligible inter-molecular force of attraction and very huge inter-molecular spacing which makes it well compressible.

8 0
3 years ago
1. A car with a mass of 2500 kg accelerates when the traffic light turns green. If the net force
soldier1979 [14.2K]

;Net force = mass of the body × acceleration of the body due to the net force

; 5000 = 2500 a...then divide both sides by 2500

; acceleration(a) = 2 m/s^2

5 0
3 years ago
What happens to the force of gravity between two masses if one mass is decreased?
Andrews [41]
<span>B. It stays the same</span>
7 0
3 years ago
Read 2 more answers
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