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Rus_ich [418]
3 years ago
6

What is the power of a machine that pushes with a force of 3 n for a distance of 9 m in 8 s?

Physics
1 answer:
dalvyx [7]3 years ago
4 0
The work done by the machine is equal to the product between the force applied and the distance over which the force is applieds, so in this case:
W=Fd=(3 N)(9 m)=27 J

And the power of the machine is equal to the ratio between the work done by the machine and the time taken:
P= \frac{W}{t}= \frac{27 J}{8 s}=3.38 W

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What are the uses of a magnet?
Doss [256]

Answer:

A magnet is used in a compass to show the direction.

Magnets are used in medical equipment.

Powerful magnets are used to lift objects

they are used in refrigerator, televisions, earphones etc

5 0
2 years ago
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An electron and a proton are held on an x axis, with the electron at x = + 1.000 m
mixas84 [53]

Answer:

  r2 = 1 m

therefore the electron that comes with velocity does not reach the origin, it stops when it reaches the position of the electron at x = 1m

Explanation:

For this exercise we must use conservation of energy

the electric potential energy is

          U = k \frac{q_1q_2}{r_{12}}

for the proton at x = -1 m

          U₁ =- k \frac{e^2 }{r+1}

for the electron at x = 1 m

          U₂ = k \frac{e^2 }{r-1}

starting point.

        Em₀ = K + U₁ + U₂

        Em₀ = \frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1}

final point

         Em_f = k e^2 ( -\frac{1}{r_2 +1} + \frac{1}{r_2 -1})

   

energy is conserved

        Em₀ = Em_f

        \frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1} = k e^2 (- \frac{1}{r_2 +1} + \frac{1}{r_2 -1})              

       

        \frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1} = k e²(  \frac{2}{(r_2+1)(r_2-1)} )

we substitute the values

½ 9.1 10⁻³¹ 450 + 9 10⁹ (1.6 10⁻¹⁹)² [ - \frac{1}{20+1} + \frac{1}{20-1} ) = 9 109 (1.6 10-19) ²( \frac{2}{r_2^2 -1} )

          2.0475 10⁻²⁸ + 2.304 10⁻³⁷ (5.0125 10⁻³) = 4.608 10⁻³⁷ ( \frac{1}{r_2^2 -1} )

          2.0475 10⁻²⁸ + 1.1549 10⁻³⁹ = 4.608 10⁻³⁷     \frac{1}{r_2^2 -1}

          \frac{2.0475 \ 10^{-28} }{1.1549 \ 10^{-37} } = \frac{1}{r_2^2 -1}

          r₂² -1 = (4.443 10⁸)⁻¹

           

          r2 = \sqrt{1 + 2.25 10^{-9}}

          r2 = 1 m

therefore the electron that comes with velocity does not reach the origin, it stops when it reaches the position of the electron at x = 1m

4 0
3 years ago
What’s the kinetic energy of the roller coaster at the top and bottom of the hill? Use . A kiddie roller coaster car has a mass
serious [3.7K]
K.E1=1/2×100×3²
=50×9
=450J
K.E2=1/2×100×36
=50×36
=1800J
0 0
3 years ago
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If F1 = 104 and F2 = 104, what will be the net force?
ladessa [460]

Answer:

208

Explanation:

add it together for the answer

3 0
3 years ago
In vacuum , the shorter the wavelength of an electromagnetic wave is , the:
skad [1K]

Answer:

Higher its Energy

Explanation:

7 0
2 years ago
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