Answer:
The answer for the question :
"Develop a chase plan that matches the forecast and compute the total cost of your plan. (Negative amounts should be indicated by a minus sign. Leave no cells blank - be certain to enter "0" wherever required. Omit the "$" sign in your response.)"
is explained in the attachment.
Explanation:
Answer:
0.0406 m/s
Explanation:
Given:
Diameter of the tube, D = 25 mm = 0.025 m
cross-sectional area of the tube = (π/4)D² = (π/4)(0.025)² = 4.9 × 10⁻⁴ m²
Mass flow rate = 0.01 kg/s
Now,
the mass flow rate is given as:
mass flow rate = ρAV
where,
ρ is the density of the water = 1000 kg/m³
A is the area of cross-section of the pipe
V is the average velocity through the pipe
thus,
0.01 = 1000 × 4.9 × 10⁻⁴ × V
or
V = 0.0203 m/s
also,
Reynold's number, Re =
where,
ν is the kinematic viscosity of the water = 0.833 × 10⁻⁶ m²/s
thus,
Re =
or
Re = 611.39 < 2000
thus,
the flow is laminar
hence,
the maximum velocity = 2 × average velocity = 2 × 0.0203 m/s
or
maximum velocity = 0.0406 m/s
Answer:
|W|=169.28 KJ/kg
ΔS = -0.544 KJ/Kg.K
Explanation:
Given that
T= 100°F
We know that
1 °F = 255.92 K
100°F = 310 .92 K
We know that work for isothermal process
Lets take mass is 1 kg.
So work per unit mass
We know that for air R=0.287KJ/kg.K
W= - 169.28 KJ/kg
Negative sign indicates compression
|W|=169.28 KJ/kg
We know that change in entropy at constant volume
ΔS = -0.544 KJ/Kg.K
Answer:
save space = 1.9626 Gibibits
Explanation:
given data
recording song time = 3 minute = 180 seconds
song per sample = 24 bits per sample
frequency = 96 kHz
surround sound system = 5.1
solution
first we get here required space for 24 bits at 96 kHz that is
required space = 24 × 96 × 10³ × 6 × 180
required space = 2.48832 × bits
as 1 Gib bit = bits
so required space = 2.48832 × bits ÷
bits
required space = 2.3174 Gibibits ...............1
and
space required to save record 16 bit at 44.1 kHz
space required = 16 × 44.1 × 10³ × 3 × 180
space required = 0.381024 × bits
space required = 0.381024 × bits ÷
bits
space required = 0.3548 Gibibits ...........2
so
we get here that save space in 16 bit at 44.1 kHz
save space = 2.3174 Gibibit - 0.3548 Gibibits
save space = 1.9626 Gibibits