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storchak [24]
3 years ago
10

A heat engine that rejects waste heat to a sink at 520 R has a thermal efficiency of 35 percent and a second- law efficiency of

60 percent. Determine the temperature of the source that supplies heat to this engine.

Engineering
1 answer:
xeze [42]3 years ago
6 0

Answer:

The source temperature is 1248 R.

Explanation:

Second law efficiency of the engine is the ratio of actual efficiency to the maximum possible efficiency that is reversible efficiency.

Given:  

Temperature of the heat sink is 520 R.

Second law efficiency is 60%.

Actual thermal efficiency is 35%.

Calculation:  

Step1

Reversible efficiency is calculated as follows:

\eta_{II}=\frac{\eta_{a}}{\eta_{rev}}

0.6=\frac{0.35}{\eta_{rev}}

\eta_{rev}=0.5834

Step2

Source temperature is calculated as follows:

\eta_{rev}=1-\frac{T_{L}}{T}

\eta_{rev}=1-\frac{520}{T}

0.5834=1-\frac{520}{T}

T = 1248 R.

The heat engine is shown below:

Thus, the source temperature is 1248 R.

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Andreas93 [3]

Answer:

The creation of "designer drugs" is outpacing the ability of society to enact laws to prohibit them.  Many of these substances have negative side effects, ranging from violent behavior to death.

 

40.  Which of the following responses to the problem would best fit the "crime control" philosophy?

a.  Government takes steps to limit the availability of ingredients used in the manufacture of designer drugs.

b.  Design a public awareness campaign to warn potential users of the dangers presented by use of these drugs.

c.  Partner with community leaders to identify underlying social issues promoting the drug subculture.

d.  Pass legislation and increase enforcement efforts to send a message of "zero tolerance" to those who manufacture, sell, and use designer drugs

The answer to the above question is

d.  Pass legislation and increase enforcement efforts to send a message of "zero tolerance" to those who manufacture, sell, and use designer drugs

Explanation:

State governments, naturally provide early response to the domestic issue of designer drug abuse than the federal government through the early banning of synthetic drug use.

State legislation on restricting designer drug use can be defined into three groups including

1. Specific synthetic substance ban

2. Ban on generic language

3. Ban based on the effect a substance has on the body.

It can be clearly demonstrated that legislation which combines this three categories is highly effective in reducing the supply and use of designer drugs.

3 0
3 years ago
: The interior wall of a furnace is maintained at a temperature of 900 0C. The wall is 60 cm thick, 1 m wide, 1.5 m broad of mat
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Answer:

<em>Heat is lost at the rate of 750 J/s or W</em>

<em>The thermal resistance is 1 K/W</em>

Explanation:

interior temperature T_{2} = 900 °C

wall thickness t = 60 cm = 0.6 m

width = 1 m

breadth = 1.5 m

thermal conductivity k = 0.4 W/m-K

outside temperature T_{1} = 150 °C

heat through the wall = ?

The area of the wall A = w x b = 1 x 1.5 = 1.5 m^2

Temperature difference dt = T_{2} - T_{1} = 900 - 150 = 750 °C

note that dt is also equal to 750 K since to convert from °C to K we'll have to add 273 to both temperature, which will still cancel out when we subtract the two temperatures.

To get the heat that escapes through the wall, we use the equation

Q = Ak\frac{dt}{t}

substituting values, we have

Q = 1.5 x 0.4 x \frac{750}{0.6} = <em>750 J/s or W</em>

Thermal resistance R_{t} = \frac{dt}{Q}

R_{t} = 750/750 =<em> 1 K/W</em>

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3 years ago
Is the ASUS ROG Strix B450-F Gaming amd ryzen 5 3600 ready?
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Answer:

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2 years ago
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The following C program asks the user for two input null-terminated strings, each stored in uninitialized 100-byte buffer, and c
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Answer:

Code is given below:

Explanation:

.data  

str1: .space 20  

str2: .space 20  

msg1:.asciiz "Please enter string (max 20 characters): "  

msg2: .asciiz "\n Please enter string (max 20 chars): "  

msg3:.asciiz "\nSAME"  

msg4:.asciiz "\nNOT SAME"  

.text

.globl main

main:  

   li $v0,4        #loads msg1  

   la $a0,msg1  

   syscall

   li $v0,8

   la $a0,str1

   addi $a1,$zero,20

   syscall          #got string to manipulate

   li $v0,4        #loads msg2

   la $a0,msg2

   syscall

   li $v0,8

   la $a0,str2

   addi $a1,$zero,20

   syscall         #got string  

       la $a0,str1             #pass address of str1  

   la $a1,str2         #pass address of str2  

   jal methodComp      #call methodComp  

   beq $v0,$zero,ok    #check result  

   li $v0,4

   la $a0,msg4

   syscall

   j exit

ok:  

   li $v0,4  

   la $a0,msg3  

   syscall  

exit:  

   li $v0,10  

   syscall  

methodComp:  

   add $t0,$zero,$zero  

   add $t1,$zero,$a0  

   add $t2,$zero,$a1  

loop:  

   lb $t3($t1)         #load a byte from each string  

   lb $t4($t2)  

   beqz $t3,checkt2    #str1 end  

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   slt $t5,$t3,$t4     #compare two bytes  

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   addi $t1,$t1,1      #t1 points to the next byte of str1  

   addi $t2,$t2,1  

   j loop  

missmatch:    

   addi $v0,$zero,1  

   j endfunction  

checkt2:  

   bnez $t4,missmatch  

   add $v0,$zero,$zero  

endfunction:  

   jr $ra

3 0
3 years ago
Two Carnot engines operate in series such that the heat rejected from one is the heat input to the other. The heat transfer from
kykrilka [37]

Answer:

Given:

high temperature reservoir T_{H} =1000k

low temperature reservoir T_{L} =400k

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The engines are said to  operate on Carnot cycle which is totally reversible.

To find the intermediate temperature between the two engines, The thermal efficiency of the first heat engine can be defined as

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The thermal efficiency of second heat engine can be written as

n_{2} =1-\frac{T_{L} }{T}

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3 years ago
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