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zloy xaker [14]

1 year ago

5

Calculate the speed of light in glycerol (n = 1.47). Use the GRASS method, write your solution on paper and insert an image of i

t below

1 answer:

Degger [83]1 year ago

6 0

The velocity of light in glycerol is 2.04 × 10⁸ m/s.

To find the answer, we need to know about the expression of velocity of light in any medium.

<h3>What's the expression of the speed of light in any medium?</h3>

Mathematically, the speed of light in any medium= C/n
C = speed of light in vaccum, n = refractive index of the medium

<h3>What's the speed of light in glycerol having refractive index of 1.47?</h3>

Speed of light in glycerol= 3×10⁸/1.47 = 2.04 × 10⁸ m/s

Thus, we can conclude that the velocity of light in glycerol is 2.04 × 10⁸ m/s.

Learn more about the speed of light in any medium here:

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Pls help me ASAP it is for a final I dont understanddddd<br> Real help

meriva

Maggie is trying to find out if the amount of sugar in a liquid affects the amount of time it takes to freeze
A good hypothesis is: The more sugar in the drink the longer it takes to freeze
Conclusion= she concludes that her hypothesis is correct as the unsweetened tea froze the fastest while the root beer took the longest time as it contained the most sugar

3 0

3 years ago

Read 2 more answers

While moving in, a new homeowner is pushing a box across the floor at a constant velocity. The coefficient of kinetic friction b

Citrus2011 [14]

Answer:

$\theta = 66.7 degree$

Explanation:

since force is applied downwards at some angle with the horizontal

so here we will have

$F_n = mg + Fsin\theta$

now we know that the box will not move if applied force is balanced by frictional force on it

so we will have

$Fcos\theta = \mu F_n$

$F cos\theta = \mu (mg + F sin\theta)$

$F(cos\theta - \mu sin\theta) = \mu mg$

$F = \frac{\mu mg}{cos\theta - \mu sin\theta}$

so here we can say

$cos\theta - \mu sin\theta > 0$

$tan\theta = \frac{1}{\mu}$

$\theta = tan^{-1}\frac{1}{\mu}$

$\theta = tan^{-1}(\frac{1}{0.43})$

$\theta = 66.7 degree$

6 0

3 years ago

The gravitational force between two objects is f. If masses of both objects are halved without changing distance between them, t

Marrrta [24]

The gravitation force is quartered when two objects' masses are halved without changing their distance.

Gravitational law states that the force of attraction and repulsion between two objects is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.

F=(KM1 M2)/r^2

K= Gravitation force constant

M1M2 = masses of the object

r = distance between objects

When M1 and M2 are halved, it becomes M1/2 and M2/2

F=(K M1/2 x M2/2)/r^2

F=(K (M1 x M2)/4)/r^2

F=(KM1 x M2)/(4r^2 )

Recall

F=(KM1 x M2)/r^2

Therefore

F=F/4

Learn more about gravitational force here:

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7 0

2 years ago

A particularly beautiful note reaching your ear from a rare stradivarius violin has a wavelength of 39.1 cm. the room is slightl

raketka [301]

The wavelength of the note is $\lambda = 39.1 cm = 0.391 m$ . Since the speed of the wave is the speed of sound, $c=344 m/s$ , the frequency of the note is
$f= \frac{c}{\lambda}=879.8 Hz$

Then, we know that the frequency of a vibrating string is related to the tension T of the string and its length L by
$f= \frac{1}{2L} \sqrt{ \frac{T}{\mu} }$
where $\mu=0.550 g/m = 0.550 \cdot 10^{-3} kg/m$ is the linear mass density of our string.
Using the value of the tension, T=160 N, and the frequency we just found, we can calculate the length of the string, L:
$L= \frac{1}{2f} \sqrt{ \frac{T}{\mu} } =0.31 m$

8 0

3 years ago

A body is dropped from the roof of a 20 m high building by how much:

USPshnik [31]

Answer:

t = 2.01 s

Vf = 19.7 m/s

Explanation:

It's know through the International System that the earth's gravity is 9.8 m/s², then we have;

Data:

Height (h) = 20 m
Gravity (g) = 9.8 m/s²
Time (t) = ?
Final Velocity (Vf) = ?

==================================================================

Time

Use formula:

$\boxed{t=\sqrt{\frac{2*h}{g}}}$

Replace:

$\boxed{t=\sqrt{\frac{2*20m}{9.8\frac{m}{s^{2}}}}}$

Everything inside the root is solved first. So, we solve the multiplication of the numerator:

$\boxed{t=\sqrt{\frac{40m}{9.8\frac{m}{s^{2}}}}}$

It divides:

$\boxed{t=\sqrt{4.08s}}$

The square root is performed:

$\boxed{t=2.01s}$

==================================================================

Final Velocity

use formula:

Vf = g * t

Replace:

Vf = 9.8 m/s² * 2.01 s

Multiply:

Vf = 19.7 m/s

==================================================================

How long does it take to reach the ground?

Takes time to reach the ground in <u>2.01 seconds.</u>

How fast does it hit the ground?

Hits the ground with a speed of <u>19.7 meters per seconds.</u>

7 0

3 years ago