Answer:
79.2 m/s
Explanation:
θ = angle at which projectile is launched = 29.7 deg
a = initial speed of launch = 130 m/s
Consider the motion along the vertical direction
v₀ = initial velocity along the vertical direction = a Sinθ = 130 Sin29.7 = 64.4 m/s
y = vertical displacement = - 108 m
a = acceleration = - 9.8 m/s²
v = final speed as it strikes the ground
Using the kinematics equation
v² = v₀² + 2 a y
v² = 64.4² + 2 (-9.8) (-108)
v = 79.2 m/s
Answer:
Option D
2 m/s
Explanation:
The speed is given by distance/time
The complete wave has a distance of 8 m (This is the wavelength)
Time taken for complete wave is 4 s
Therefore, velocity= 8 m/ 4 s= 2 m/s
The amplitude is the distance between crest and trough hence 9 m- 6 m= 3 m
Frequency is 1/period and in this case period is 4 s hence frequency= 1/4= 0.25 Hz
Essentially, what we wanted is velocity
A 300-kg bear grasping a vertical tree slides down at constant velocity. The friction force between the
tree and the bear is
Answer:
123 J transfer into the gas
Explanation:
Here we know that 123 J work is done by the gas on its surrounding
So here gas is doing work against external forces
Now for cyclic process we know that
so from 1st law of thermodynamics we have
so work done is same as the heat supplied to the system
So correct answer is
123 J transfer into the gas
