Answer:
The displacement is 
The distance is 
Explanation:
From the question we are told that
The height from which the ball is dropped is 
The height attained at the first bounce is 
The height attained at the second bounce is 
The height attained at the third bounce is 
Note : When calculating displacement we consider the direction of motion
Generally given that upward is positive the total displacement of the ball is mathematically represented as

Here the 0 show that there was no bounce back to the point where Billy released the ball

=> 
Generally the distance covered by the ball is mathematically represented as

The 2 shows that the ball traveled the height two times

=> 
<em>Kinetic Energy</em>
=><em><u>It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.</u></em>
<em>Potential</em><em> </em><em>Energy</em><em> </em>
<u><em>=</em><em>></em><em>potential energy is the energy held by </em></u><em><u>an</u></em>
<em><u> object because of its position relative to </u></em><em><u>other</u></em>
<em><u> objects, stresses within itself, its </u></em><em><u>electric</u></em>
<em><u> charge, or other factors.</u></em>
<h2>Difference:</h2>
=>Potential energy is a <u>stored</u> energy on the other hand kinetic energy is the energy of an object or a system's particle in <em><u>Motion</u></em>.
"Fig is attacted with answer"
Answer:
a) d = 33.72 m
b)
= 26 m/s
c) β = 71.08°
Explanation:
a)
When an object is thrown into the air under the effect of the gravitational force, the movement of the projectile is observed. Then it can be considered as two separate motions, horizontal motion and vertical motion. Both motions are different, so that they can be handled independently.
Given data:
time = t = 4.00 s
Height = h = 20 m
Angle = θ = 60°
Horizontal distance = d = ?
Using 2nd equation of motion

-20 =
(4) + 0.5(-9.8)(4)²
(4) = 58.4
= 14.6 m/s
This is vertical component of velocity when the ball is on the roof. To calculate the Final velocity and horizontal component, we use
=
/ sinθ
= 14.6 / sin 60
= 16.86 m/s
=
cosθ
= 16.86 cos 60
= 8.43 m/s
To calculate the horizontal distance
d =
t
d = (8.43)(4)
d = 33.72 m
b)
We know the values of Landing angle, height of roof, time of flight. In part a, We calculate the landing velocity of the ball and also its horizontal and vertical component. As the ball followed the projectile path, and we know that in projectile motion the horizontal component of the velocity remain constant throughout his motion. So there is no acceleration along horizontal path.
So,
= 
but the vertical component of velocity vary with and there is an acceleration along vertical direction which is equal to gravitation acceleration g.
So,
g = (
-
) / t
9.8 = 14.6 -
) / 4
= 24.6 m/s
= 
= 
= 26 m/s
c)
cos β =
/ 
β = cos⁻¹ (8.43 / 26)
β = 71.08°
Answer:
The velocity of the hay bale is - 0.5 ft/s and the acceleration is 
Solution:
As per the question:
Constant velocity of the horse in the horizontal, 
Distance of the horse on the horizontal axis, x = 10 ft
Vertical distance, y = 20 ft
Now,
Apply Pythagoras theorem to find the length:


Now,
(1)
Differentiating equation (1) w.r.t 't':


where
= Rate of change of displacement along the horizontal
= Rate of change of displacement along the vertical
= velocity along the x-axis.
= velocity along the y-axis



Acceleration of the hay bale is given by the kinematic equation:





Answer:
102 kg.m/s
Explanation:
m = Mass of hammer = 12 kg
v = Final velocity = 8.5 m/s
u = Initial velocity = 0
t = Time taken = 8 ms
Force acting over a given amount of time or change in momentum is known as impulse.
Impulse

Impulse given to the nail is 102 kg.m/s