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svlad2 [7]
2 years ago
8

a man carries a hand bag by hanging on his hand and moves horizontally where the bag does not move up or down. What is the work

done on the bag? The man gets tired after sometime of the movement. Why
Physics
1 answer:
vlada-n [284]2 years ago
3 0

The work that the man does is the scalar product of the force applied by the man and the horizontal displacement of the bag.

<h3>What is the work done?</h3>

In Physics, we define the work done as the product of the of force and distance. Hence, we generally define the work done as that which occurs when the force applied moves a distance in the direction of the force. This implies that the work done is not a vector but a  scalar quantity.

In relation to the man and the bag, the work done is the product of the force that the man applies and the displacement of the bag. As such, the reason for the tiredness of the man is that the internal energy that he possesses is transferred to moving the bag.

Thus, the work that the man does is the scalar product of the force applied by the man and the horizontal displacement of the bag.

Learn more about work done:brainly.com/question/13662169

#SPJ1

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Answer:

v=0.94 m/s

Explanation:

Given that

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The maximum acceleration of system will ω²X.

ω = natural frequency

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For top stop slipping

μ g  =ω²X

We know for spring mass system natural frequency given as

\omega=\sqrt{\dfrac{k}{M+m}}

By putting the values

\omega=\sqrt{\dfrac{150}{5.67+1}}

ω = 4.47 rad/s

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By putting the values

0.45 x 10 = 4.47² X

X = 0.2 m

From energy conservation

\dfrac{1}{2}kX^2=\dfrac{1}{2}(m+M)v^2

kX^2=(m+M)v^2

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v=0.94 m/s

This is the maximum speed of system.

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