1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alekssandra [29.7K]
3 years ago
6

Can someone answer this science question NO LINKS !!!!

Physics
1 answer:
Step2247 [10]3 years ago
3 0

Answer:

Point x.

Explanation:

The potential energy of an object is simply defined as the energy stored in an object by virtue of its location. Mathematically, it is expressed as:

PE = mgh

Where

PE => is the potential energy

m => is the mass of the object

g => is acceleration due to gravity

h => is the height

From the formula i.e PE = mgh, we can see that the potential energy (PE) is directly proportional to the height (h).

This simply indicates that as the height increases, the potential energy will increase and as the height decreases, the potential energy will also decrease.

Now, let us consider the question given above.

Point x indicates the greatest height attained by the ball. Therefore, the ball will have it's greatest potential energy at point x.

You might be interested in
The mass of a star is 1.210×1031 kg and it performs one rotation in 20.30 days. Find its new period (in days) if the diameter su
balandron [24]

The new period will be 2.486 days.

<h3>What is the period?</h3>

The period is found as the ratio of the angular displacement and the angular velocity. Its unit is the second and is denoted by t. The value of time needed to complete the rotation is the total period.

Given data;

Mass of a star,m= 1.210×10³¹ kg

The time period for one rotation of the star, T = 20.30 days

D' = 0.350 D

R' = 0.350 R

From the law of conservation of angular momentum;

\rm  I \omega = I' \omega' \\\\ \frac{2}{5} MR^2 \times \frac{2 \pi }{T}=\frac{2}{5} MR'^2 \\\\ R^2 \times \frac{1}{T}= R'^2  \times \frac{1}{T} \\\\ T' = \frac{R'^2T}{R^2}  \\\\ T' = \frac{(0.350 R)^2 \times 26.1 }{R^2} \\\\T' = 0.1225 \times 20.30 \\\\ T'= 2.486 \ days

Hence, the new period will be 2.486 days.

To learn more about the period, refer to the link;

brainly.com/question/569003

#SPJ1

8 0
2 years ago
dopasuj wartości pracy z ramki do przedstawionych sytuacji ,a nastepnie wyraż te prace w dżulach uwaga jedna wartośc pracy nie b
Eduardwww [97]

Answer:

A (samolot) - 200 MJ = 200000000 J

B (dźwig) - 800 kJ = 800000 J

C (podnośnik)-1.6 kJ = 1600 J

Explanation:

Całą część pytania można znaleźć na poniższym schemacie.

Z diagramu załączonego poniżej; mamy

A - samolot lotniczy

B - dźwig

C - podnoszenie ciężarów

Wszyscy to wiemy ;

1kJ = 1000 J

1MJ = 1000000 J

Mamy cztery opcje; i.e 200 MJ, 800 kJ, 1.6 kJ  and 250 mJ

Z czterech opcji można wykluczyć 250 mJ, ponieważ jest to 0,25 J, co przedstawia bardzo niską energię w porównaniu z trzema warunkami pokazanymi na schemacie.

Więc:

A (samolot) - 200 MJ = 200000000 J

B (dźwig) - 800 kJ = 800000 J

C (podnośnik)-1.6 kJ = 1600 J

Największą pracę wykona samolot. Jest tak, ponieważ ma bardzo dużą masę i bardzo dużą prędkość. W związku z tym istnieje potrzeba wytworzenia ogromnej ilości ciepła i energii.

Z drugiej strony żuraw może podnieść ładunek o wiele większy i przewyższa ciężar ciężaru, więc praca wykonywana przez dźwig musi być zdecydowanie większa niż praca ciężarka.

3 0
3 years ago
By what factor should the length of a simple pendulum be changed in order to triple the period of vibration?
kenny6666 [7]

Answer:

increased by 9 times

Explanation:

As the period of a simple pendulum is defined as the following formula

T = 2\pi\sqrt{\frac{L}{g}}

where L is the length of the pendulum and g is the constant gravitational acceleration. Since L is under a square root, if you want to triple the period of vibration, L must be increased by 9 times so that \sqrt{9} = 3

4 0
3 years ago
You are driving at 75 km/h. Your sister follows in the car behind at 75 km/h. When you honk your horn, your sister hears a frequ
OLga [1]

The ideal concept for solving this question is based on the Doppler effect, for which it is indicated that the source's listening frequency changes as the distance and the relative speed between the receiver and the transmitter are also changed. However, if the relative velocity between the two objects is zero as in the particular case presented (since both travel at 75km / h) we have that there will be no change in frequency.

Therefore the frequency that I hear and that my sister would listen would be the same.

5 0
3 years ago
Which level of the energy pyramid contains the most energy​
Anestetic [448]

Answer:

lowest level contains more energy

Explanation:

7 0
3 years ago
Other questions:
  • Cross country skier moves 32 m west word than 54 m east word and finally 68 m westward what is the distance moved?
    9·1 answer
  • Can someone plz help me with this
    7·1 answer
  • A student pushes on a crate with a force of 100 Newtons directed to the right.
    13·1 answer
  • A 600-kg car traveling at 30.0 m/s is going around a curve having a radius of 120 m that is banked at an angle of 25.0°. The coe
    14·1 answer
  • A toboggan approaches a snowy hill moving at 12.4 m/s. The coefficients of static and kinetic friction between the snow and the
    9·1 answer
  • What is your REASONING for this CLAIM? EXPLAIN WHY your claim is true.
    12·1 answer
  • In addition to a reference point you also need distance and __________ to describe location
    8·1 answer
  • If electrical current is moving through a horizontal wire toward your face, what direction is the induced magnetic field?
    10·1 answer
  • Why did the ice melt so quick science method pls help ‍♀️‍♀️
    8·1 answer
  • Predict the magnitude of the gravitational force....
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!