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belka [17]
3 years ago
6

A bouncing ball has the greatest amount of ___________ energy at the top of its bounce.

Physics
2 answers:
dybincka [34]3 years ago
7 0
I think it is kinetic  cuz  it has most of it at the top
Masteriza [31]3 years ago
4 0
A bouncing ball has the greatest amount of<u> kinetic</u> energy at the top of its bounce.
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A bicyclist steadily speeds up from rest to 6.00m/s in 7.30s.
Simora [160]

Answer:

21.899 m

Explanation:

The explanation here is a little differe because we are starting from rest. So, everyone does physics a little differently, but what I would start with is trying to find the accelaration. I've given the formula, now you are able to plug this into the displacement formula where you Velocity Initial = 0m/s (Since you are starting from rest) and V final = 6.00 m/s...

You just plug numbers into the formula after solving for accelaration and do some simple algebra! I hope this helps! I am attaching a new pdf for visuals! If you can't open it let me know! Also there is a star by accelaration because I didn't know if I spelled it right, sorry!

8 0
3 years ago
What is the weight of a 82.1 kg object on Jupiter, where the acceleration due to gravity is 24.5 m/s2?
victus00 [196]
Answer: 1,031.06 pounds
3 0
3 years ago
Why don’t we feel the gravitational force of a large object such as a skyscraper semi-truck?
Kobotan [32]

Answer:

Se the explanation below

Explanation:

We do not feel these forces of these bodies, because they are very small compared to the force of Earth's attraction. Although its mass is greater than that of a human being, its mass is not compared to the Earth's mass. In order to understand this problem we will use numerical data and the universal gravitation formula, to give validity to the explanation.

<u>Force exerted by the Earth on a human being</u>

<u />

F=G*\frac{m_{1}*m_{2}}{r^2}

Where:

G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]

m1 = mass of the person = 80 [kg]

m2 = mass of the earth 5.97*10^24[kg]

r = distance from the center of the earth to the surface or earth radius = 6371 *10^3 [m]

<u />

Now replacing we have

F = 6.673*10^{-11} *\frac{80*5.97*10^{24}}{(6371*10^{3})^{2}  } \\F = 785[N]

<u>Force exerted by a building on a human being</u>

<u />

Where:

G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]

m1 = mass of the person = 80 [kg]

m2 = mass of the earth 300000 [ton] = 300 *10^6[kg]

r = distance from the building to the person = 2[m]

F = 6.673*10^{-11}*\frac{80*300*10^6}{2^{2} }  \\F= 0.4 [N]

As we can see the force exerted by the Earth is 2000 times greater than that exerted by a building with the proposed data.

8 0
3 years ago
PLEASE HELP!!!!!!!!! 30 POINTS
ivolga24 [154]

Answer: experiment data is the things you do in the experiment and the result is the answer

4 0
3 years ago
3.
nikitadnepr [17]
The answer is
B:because
8 0
3 years ago
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