Answer: a) Cnew=Cinitial ; b) λouter new= 2*λ outer initial
Explanation: In order to explain this question we have to take into account the expression of teh cylinder capacitor given by:
C/L= (2*π*εo)/ln (b/a)= where b and a are the outer and inner radius, respectively. L is the length of the capacitor.
As you can se this formule depents of geometrical characateristics of the capacitor.
The capacitance is the same after change the densities of charge.
On the other hand,
The new charge in each cylinder ( inner and outer) is determined
The new potential is 2 times the initial one so
V new= 2* Vinitial
Also we know that
Vnew= Q/C= λnew*L/C; C= constant
using this formule and considering that V new is doubled then the charge per one meter length, is also doubled .
This is as follow:
Vnew= λnew*L/C=
λnew = (2*Vinitial)* C/L= 2 (λ initial)
Then λouter new = 2* λouter initial
<h2>Electrostatic Potential Decreases</h2>
Explanation:
- If the spacing between two closely spaced oppositely charged parallel plates is decreased the electrostatic potential difference between the plates will decrease.
- An electrostatic potential that is also referred to as the electric field potential or potential drop is the amount of work required to replace a unit of charge from a reference point to a specific point inside the electric field without any change in acceleration.
- Therefore, if the distance will decrease between oppositely charged plates there will be more affinity to attract which will reduce the amount of work done thus decreasing the electric potential
∴ The Correct option is (b)
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