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-Dominant- [34]

2 years ago

6

What are three biotic factors that can affect an organism after death?

2 answers:

Anestetic [448]2 years ago

7 0

Brain , blood , Nutrisystem !!!!!!’

Dvinal [7]2 years ago

7 0

Answer:

the three are scavengers predators and decomposers

Explanation:

The three biotic factors that can affect an organism after death are scavengers, predators, and decomposers that can breakdown and destroy the organism. an abiotic factor that can prevent the organism from becoming preserved after it has been buried would be groundwater.

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joe spend 8 on lunch and 6.50 on dry cleaning . He also buys 2 shirts that each cost the same smount. joe spend a total of $52 w

Gnesinka [82]

8+6.5+2x=52
52/2=8+6.5+x
26=8+6.5+x
26-8-6.5=x
11.5=x

6 0

3 years ago

We can estimate the age of an open cluster of stars by examining _________.

ololo11 [35]

I think the answer is C

Hope this help

5 0

3 years ago

Rahul runs a distance of 12

Radda [10]

Answer:

Rita runs faster

Explanation:

To obtain the answer to the question given, we determine the speed of Rita. This can be obtained as follow:

Distance = 1.6 km

Time = 15 mins

Speed =?

Next, we shall convert 15 mins to hour. This can be obtained as follow:

60 mins = 1 h

Therefore,

15 mins = 15 mins × 1 h / 60 mins

15 mins = 0.25 h

Thus, 15 mins is equivalent to 0.25 h.

Finally, we shall determine speed of Rita as follow:

Distance = 1.6 km

Time = 0.25 h

Speed =?

Speed = distance / time

Speed = 1.6 / 0.25

Speed = 6.4 Km/h

Thus Rita's speed is 6.4 Km/h

Comparing the speed of Rahul and Rita

Rahul's speed = 4.5 km/h

Rita's speed = 6.4 Km/h

We can see that Rita's speed is greater than Rahul's speed. This simply indicates that Rita runs faster than Rahul.

4 0

2 years ago

Divergent plate boundaries are when plates

umka21 [38]

Explanation:

Move past each other.

Have a good day.

7 0

2 years ago

Read 2 more answers

neptune is an average distance of 4.5×10^12m from the sun. Estimate the length of the Neptunian year.

Vikentia [17]

As per Kepler's third law we know that

$\frac{T_1^2}{T_2^2} = \frac{R_1^3}{R_2^3}$

now here we know that

$T_1$ = year of Neptune

$T_2$ = year of Earth

$R_1$ = distance of Neptune from Sun

$R_2$ = Distance of Earth from Sun

so now we will have

$\frac{T_1^2}{1} = \frac{(4.5 \times 10^{12})^3}{(1.5 \times 10^11)^3}$

$T_1^2 = 27000$

$T_1 = 164.3 years$

so length of year of Neptune is 164.3 years

6 0

2 years ago