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Yuki888 [10]
3 years ago
7

How many earths could fit inside jupiter

Physics
1 answer:
Snezhnost [94]3 years ago
8 0

1,300 or more.

hope this helped :)

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If the swimmer starts at rest, slides without friction, and descends through a vertical height of 2.41 m
AveGali [126]

Answer:

6.88 m/s

Explanation:

The Conservation of Energy states that:

Initial Kinetic Energy + Initial Potential Energy = Final Kinetic Energy + Final Potential Energy

So we can write

mgh_{i}+\frac{1}{2}mv_{i} ^{2}=mgh_{f}+\frac{1}{2}mv_{f} ^{2}

We can cancel the common factor of m which leaves us with

gh_{i}+\frac{1}{2}v_{i} ^{2}=gh_{f}+\frac{1}{2}v_{f} ^{2}

Lets solve for v_f

gh_{i}+\frac{v_{i} ^{2}}{2}=gh_{f}+\frac{v_{f} ^{2}}{2}

Subtract gh_f from both sides of the equation.

gh_{i}+\frac{v_{i} ^{2}}{2}-gh_{f}=\frac{v_{f} ^{2}}{2}

Multiply both sides of the equation by 2.

2(gh_{i}+\frac{v_{i} ^{2}}{2}-gh_{f})={v_{f} ^{2}

Simplify the left side.

Apply the distributive property.

2(gh_{i})+2\frac{v_{i} ^{2}}{2}+2(-gh_{f})={v_{f} ^{2}

Cancel the common factor of 2.

2gh_{i}+v_{i} ^{2}-2gh_{f}={v_{f} ^{2}

Take the square root of both sides of the equation to eliminate the exponent on the right side.

{v_{f}=\sqrt{2gh_{i}+v_{i} ^{2}-2gh_{f}}

We are given g,v_{i},h_{i},h_{f}.

We can now solve for the final velocity.

{v_{f}=\sqrt{(2*9.81*2.41)+(0^{2})-(2*9.81*0)

Anything multiplied by 0 is 0.

{v_{f}=\sqrt{2*9.81*2.41

{v_{f}=\sqrt{47.2842

v_f=6.88

7 0
1 year ago
Please help on this one?
Gnoma [55]
The answer is C thirty
8 0
3 years ago
A square loop of side length a =2.9 cm is placed a distance b = 1.2 cm from a long wire carrying a current that varies with time
daser333 [38]

Answer:

Explanation:

Magnetic field due to a long wire

B =  (  μ₀ / 4π ) x 2 I / r  ( I is current through the wire )

= (μ₀ Q t ) / ( 2 π r )                    [ I = Q t ]

b )  Magnetic field will change through the length of the square shaped loop . So we shall have to take the help of integration to calculate the flux through the loop.

Flux Φ = ∫ B dA

=∫ (  μ₀ / 4π ) x 2 I / r  dA

10⁻⁷ x 2 I ∫ a dr/r

2 x 10⁻⁷ x Qt x a [ ln (2.9+1.2) / 1.2  ]

4.6 x 10⁻⁷ x 2.9 x 10⁻² t  ln 4.1 / 1.2

16.4  x 10⁻⁹ t

Φ( t ) =  16.4 x 10⁻⁹ t

Induced emf  = dΦ( t ) / dt = 16.4 x 10⁻⁹ v

current

16.4 x 10⁻⁹  / 2.5

= 6.56 x 10⁻⁹

5 0
3 years ago
A quarter is 2.4 millimeters thick. How tall are the following stacks of quarters?
Lemur [1.5K]
A. 4.8 millimeters
B. 9.6 millimeters
C. 48 millimeters
D. 9,600 millimeters or 9.6 meters
There are 1000 mm in a meter
3 0
3 years ago
Consider two identical 4-kg pieces of roast beef. the first piece is baked as a whole, while the second is baked after being cut
Molodets [167]

Too cook the beef, the heat should penetrate to the deepest layer of the meat. Let say that the meat is cubical with 10cm width. To penetrate the core of the meat, the heat need to travel 5 cm from any side of the meat. If the meat cut into two similar pieces, the deepest core of the meat will be exposed to the heat directly.

Now the deepest core is not 5 cm anymore, it will become 2.5 cm. So the heat has to penetrate a thinner layer, thus make it cooked faster.

4 0
3 years ago
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