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babymother [125]
1 year ago
6

What is the safest method to determine electrical current

Physics
1 answer:
Kisachek [45]1 year ago
4 0
Break the circuit and apace a meter actually within the circuit.
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What is the acceleration of the object?<br> m/s²
Orlov [11]

Answer:

-2.5m/s^2

Explanation:

10-40/12-0=-2.5

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2 years ago
Please help with 9 &amp; 10
Tanzania [10]
Add all the sec. and all the meter's and then add the meter's and sec. together
4 0
3 years ago
Which of the following statements are true? Positively charged objects attract other positively charged objects. Negatively char
butalik [34]
The statement that is true is that positively charged objects attract negatively charged objects. This is due to a law that states 'like forces attract while unlike forces repel. This same concept applies to magnetism. If you put two similar poles together, for example; if you place two south poles together. You feel a separating force between the two poles. But if you place two opposite poles together they attract each other. Hope i helped. <span />
7 0
3 years ago
Read 2 more answers
In a football game, the running back takes a handoff and begins running toward midfield at 3.21 yards/s . As he moves through hi
Inessa [10]

Given Information:

Initial speed = u = 3.21 yards/s

Acceleration = α  = 1.71 yards/s²

Final speed = v = 7.54 yards/s

Required Information:

Distance = s = ?

Answer:

Distance = s = 13.61

Explanation:

We are given the speeds and acceleration of the runner and we want to find out how much distance he covered before being tackled.

We know from the equations of motion,

v² = u² + 2αs

Where u is the initial speed of the runner, v is the final speed of the runner, α is the acceleration of the runner and s is the distance traveled by the runner.

Re-arranging the above equation for distance yields,

2αs = v² - u²

s = (v² - u²)/2α

s = (7.54² - 3.21²)/2×1.71

s = 46.55/3.42

s = 13.61 yards

Therefore, the runner traveled a distance of 13.61 yards before being tackled.

8 0
3 years ago
a person complete a 100m race in 11s. He accelerates for the first two second and then maintains the velocity till the end. what
hjlf

The maximum velocity reached by the person is determined as 11.1 m/s.

<h3>Area under velocity - time graph</h3>

The area under the velocity time graph is the total displacement of the person.

Total Area = area of triangle formed during first 2 seconds + area of rectangle during the last 8 seconds

100 = ¹/₂(2v) + v(11 - 2)

where;

  • v is the maximum velocity

100 = v + 8v

100 = 9v

v = 100/9

v = 11. 1 m/s

Thus, the maximum velocity reached by the person is determined as 11.1 m/s.

Learn  more about maximum velocity here: brainly.com/question/20595261

#SPJ1

4 0
1 year ago
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