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Ivenika [448]
2 years ago
5

Earth's _____ cycle moves water from one reservoir to another. This cycling of materials is one of Earth's dynamic processes.

Physics
2 answers:
Alenkinab [10]2 years ago
7 0
Earth's HYDROLOGIC cycle moves water from one reservoir to another.
Advocard [28]2 years ago
3 0

Answer:

Explanation:

If California is the site of several plate boundaries, we would expect to see mostly metamorphic rock at the boundary sites. Think about California. It IS the site of several plate boundaries. We would expect heat, pressure and re-crystallization to occur here and that would result in metamorphic rock.

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A cyclist rides at a constant speed of 4. 5 m/s around a curve. If the centripetal acceleration is 29 m/s2, what is the radius o
QveST [7]

Answer:

a = v^2 / R = 4.5^2 / R = 29

R = 4.5^2 / 29 = .70 m

     

3 0
2 years ago
Sliding friction is _ than the static friction.
Alona [7]

Answer:

less

Explanation:

Sliding friction is always less than static friction. This is because in sliding friction, the bodies slide with each other and thus the effect of friction is not more. However, it does not happen in the case of static friction.

4 0
2 years ago
Urgent if earths gravitational field strength is 10 N/kg how many newtons does a 30kg object weigh
egoroff_w [7]

weight of 30 Kg object= 300 N

Explanation:

Weight= m I

m= mass=30 kg

I= gravitational filed strength= 10 N/kg

weight=30 (10)

weight=300 N

5 0
2 years ago
What is the force of a lead ball that starts with a momentum of 7 kg*m/s and end with a momentum of 22 kg*m/s over a time of 31
Gwar [14]

Answer:

F = 0.483 N

Explanation:

Initial momentum, P_i= 7\ kg-m/s

Final momentum, P_f= 22\ kg-m/s

Time, t = 31 s

We need to find the force of a lead ball. We can use here the impulse momentum theorem.

\text{Change in momentum}=F\times t

F is force

P_f-P_i=Ft\\\\F=\dfrac{P_f-P_i}{t}\\\\F=\dfrac{22-7}{31}\\\\F=0.483\ N

So, the force is 0.483 N.

6 0
2 years ago
A car enters a level, unbanked semi-circular hairpin turn of 100 m radius at a speed of 28 m/s. The coefficient of friction betw
meriva

Answer:

As  28m/s = 28m/s

Explanation:

r = the radius of the curve

m =  the mass of the car

μ = the coefficient of kinetic friction

N = normal reaction

When rounding the curve, the centripetal acceleration is

a = \frac{v^{2}}{r}

therefore

\mu mg = m \frac{v^{2}}{r} \\\\ \mu =  \frac{v^{2}}{rg}

v = \sqrt{\mu rg}

\mu = \sqrt{0.8 \times 100\times9.8} \\\\= 28m/s

As  28m/s = 28m/s

8 0
3 years ago
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