Answer:
Explanation:
<u>Given Data:</u>
Initial Volume = 
= 7.0 L
Initial Temperature = 
= 300 °C + 273 = 573 K
Final Temperature = = 25.0 °C + 273 = 298 K
<u>Required:</u>
Final Volume = 
= ?
<u>Formula:</u>
<u>[Charles Law] </u>
<u>Solution:</u>
Put the givens
![\displaystyle \frac{7}{573 } =\frac{V_2}{298} \\\\0.01 = \frac{V_2}{298} \\\\\times 298 \ to \ both \ sides\\\\0.01 \times 298 = V_2\\\\3.64 \ L =V_2\\\\\boxed{V_2 =3.64 \ L}\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B7%7D%7B573%20%7D%20%3D%5Cfrac%7BV_2%7D%7B298%7D%20%5C%5C%5C%5C0.01%20%3D%20%5Cfrac%7BV_2%7D%7B298%7D%20%5C%5C%5C%5C%5Ctimes%20298%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C0.01%20%5Ctimes%20298%20%3D%20V_2%5C%5C%5C%5C3.64%20%5C%20L%20%3DV_2%5C%5C%5C%5C%5Cboxed%7BV_2%20%3D3.64%20%5C%20L%7D%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Answer:
pH = 10
The solution is basic.
Explanation:
A solution contains 1 × 10⁻⁴ M OH⁻ ions. First, we will calculate the pOH.
pOH = -log [OH⁻]
pOH = -log 1 × 10⁻⁴
pOH = 4
We can find the pH of the solution using the following expression.
pH + pOH = 14.00
pH = 14.00 - pOH = 14.00 - 4 = 10
Since the pH > 7, the solution is basic.
Answer : It’s C.
Cccccccccccccccccccccccccccccccccccccccc
Answer:
Mass = 208.26 g
Explanation:
Given data:
Volume of water = 40.0 mL
Volume of water + copper = 63.4 mL
Volume of copper = ?
Density of copper = 8.9 g/cm³
Mass of copper = ?
Solution:
Volume of copper:
Volume of copper = (Volume of water + copper ) - Volume of water
Volume of copper = 63.4 mL - 40.0 mL
Volume of copper = 23.4 mL
Mass of copper:
density = mass/volume
8.9 g/cm³ = mass/23.4 mL
cm³ = mL
Mass = 8.9 g/mL × 23.4 mL
Mass = 208.26 g
Answer: 5 is the molarity
Explanation:
The molarity formula is moles over liters and that in your case is 2.50 moles divided by .500 L which results in 5 which is your answear hope this helped god bless
