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katrin [286]
2 years ago
14

2. 3. 4. 5. 6. 7. A(n)results when a vehicle loses part or all of its grip on the road. is a technique that can be applied when

trying to move your vehicle out of deep snow. The action of a vehicle's rear end sliding out to a side is called a(n) is a technique of reducing your speed as quickly as possible while maintaining control of your vehicle. Driving at a speed where the stopping distance of your vehicle is longer than the distance you can see with your headlights is called occurs when a tire loses road surface contact and rises on top of water. It is a(n)when your front tires begin 1 18 1 1 to plow and your vehicle is not responding, or not responding as quickly as it should, to a steering input.
Physics
1 answer:
dexar [7]2 years ago
7 0

Answer:

1) Skid

2)<u> </u>Rocking

3) Oversteer situation

4) Controlled breaking

5) Overdriving headlights

6) Hydroplaning

7) Understeer situation

Explanation:

1) A <u>skid</u> results when a vehicle loses part or all of its grip on the road

2)<u> Rocking</u> is a technique that can be applied when trying to move your vehicle out of deep snow

3) The action of vehicle's rear end sliding out to a side is called an <u>oversteer situation</u>

4) <u>Controlled breaking</u> is a technique of reducing your speed as quick as possible while maintaining control of your vehicle

5) Driving at a speed where the stopping distance of your vehicle is longer than the distance you can see with your headlights is called <u>overdriving headlights</u>

6) <u>Hydroplaning</u> occurs when a tire loses road surface contact and rises on top of water

7) It is an <u>understeer situation</u> when your front tires begin to plow and your vehicle is not responding or not responding as quickly as it should, to a steering point

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On a horizontal surface is located
Ierofanga [76]

By Newton's second law, the net vertical force acting on the object is 0, so that

<em>n</em> - <em>w</em> = 0

where <em>n</em> = magnitude of the normal force of the surface pushing up on the object, and <em>w</em> = weight of the object. Hence <em>n</em> = <em>w</em> = <em>mg</em> = 196 N, where <em>m</em> = 20 kg and <em>g</em> = 9.80 m/s².

The force of static friction exerts up to 80 N on the object, since that's the minimum required force needed to get it moving, which means the coefficient of <u>static</u> friction <em>µ</em> is such that

80 N = <em>µ</em> (196 N)   →   <em>µ</em> = (80 N)/(196 N) ≈ 0.408

Moving at constant speed, there is a kinetic friction force of 40 N opposing the object's motion, so that the coefficient of <u>kinetic</u> friction <em>ν</em> is

40 N = <em>ν</em> (196 N)   →   <em>ν</em> = (40 N)/(196 N) ≈ 0.204

And so the closest answer is C.

(Note: <em>µ</em> and <em>ν</em> are the Greek letters mu and nu)

3 0
3 years ago
At which position is the LOWEST potential energy?
Ad libitum [116K]
The answer is position 3, because it is at its lowest point.

Potential Energy is “stored energy.” It is energy that is ready to be converted or released as another type of energy. We most often think of potential energy as gravitational potential energy. When objects are higher up, they are ready to fall back down. When you stretch an object and it has a tendency to return to its original shape, it is said to have elastic potential energy. Chemical potential energy is the stored energy in a substance’s chemical structure that can be released in a chemical reaction or as heat.

7 0
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A human being can be electrocuted if a current as small as 55 mA passes near the heart. An electrician working with sweaty hands
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Answer:

The lethal voltage for the electrician under those conditions is 126.5 V.

Explanation:

To discover what is the lethal voltage to the electrician we need to find out what is the voltage that produces 55 mA = 0.055 A when across a resistance of 2300 Ohms (Electrician's body resistancy). For that we'll use Ohm's Law wich is expressed by the following equation:

V = i*R

Where V is the voltage we want to find out, i is the current wich is lethal to the electrician and R is his body resistance. By applying the given values we have:

V = 0.055*2300 = 126.5 V.

The lethal voltage for the electrician under those conditions is 126.5 V.

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