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katrin [286]
3 years ago
14

2. 3. 4. 5. 6. 7. A(n)results when a vehicle loses part or all of its grip on the road. is a technique that can be applied when

trying to move your vehicle out of deep snow. The action of a vehicle's rear end sliding out to a side is called a(n) is a technique of reducing your speed as quickly as possible while maintaining control of your vehicle. Driving at a speed where the stopping distance of your vehicle is longer than the distance you can see with your headlights is called occurs when a tire loses road surface contact and rises on top of water. It is a(n)when your front tires begin 1 18 1 1 to plow and your vehicle is not responding, or not responding as quickly as it should, to a steering input.
Physics
1 answer:
dexar [7]3 years ago
7 0

Answer:

1) Skid

2)<u> </u>Rocking

3) Oversteer situation

4) Controlled breaking

5) Overdriving headlights

6) Hydroplaning

7) Understeer situation

Explanation:

1) A <u>skid</u> results when a vehicle loses part or all of its grip on the road

2)<u> Rocking</u> is a technique that can be applied when trying to move your vehicle out of deep snow

3) The action of vehicle's rear end sliding out to a side is called an <u>oversteer situation</u>

4) <u>Controlled breaking</u> is a technique of reducing your speed as quick as possible while maintaining control of your vehicle

5) Driving at a speed where the stopping distance of your vehicle is longer than the distance you can see with your headlights is called <u>overdriving headlights</u>

6) <u>Hydroplaning</u> occurs when a tire loses road surface contact and rises on top of water

7) It is an <u>understeer situation</u> when your front tires begin to plow and your vehicle is not responding or not responding as quickly as it should, to a steering point

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Answer:

1.35 m/s in the +x direction

Explanation:

Mass of can of coffee, m = 2.4 kg

Initial velocity of can of coffee, u = 1.5 m/s

Mass of box of macaroni, M = 1.2 kg

Initial velocity of box of macaroni, U = 0 m/s

Final velocity of can of coffee, v = 0.825 m/s

We can find the final velocity of the box of macaroni, V, by using the Principle of Conservation of momentum:

Total initial momentum = Total final momentum

Momentum is given as the product of mass and velocity. Hence:

mu + MU = mv + MV

(2.4 * 1.5) + (1.2 * 0) = (2.4 * 0.825) + (1.2 * V)

3.6 + 0 = 1.98 + 1.2V

1.2V = 3.6 - 1.98 = 1.62

=> V = 1.62/1.2

V = 1.35 m/s

The final velocity of the box of macaroni is 1.35 m/s and it is in the +x direction.

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If the angle between the vector and the y-axis is  Θ ,
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the 200 g baseball has a horizontal velocity of 30 m/s when it is struck by the bat, B, weighing 900 g, moving at 47 m/s. during
Ivanshal [37]

Solution :

Given :

Mass of the baseball, m = 200 g

Velocity of the baseball, u = -30 m/s

Mass of the baseball after struck by the bat, M = 900 g

Velocity of the baseball after struck by the bat, v = 47 m/s

According to the conservation of momentum,

Mv+mu=Mv_1+mv_2

(900 x 47) + (200 x -30)  = (900 x v_1) + (200 x v_2)

36300 =  (900 x v_1) + (200 x v_2)

9v_1 + 2v_2 = 363 ..............(i)

9v_1 = 363 - 2v_2

v_1=\frac{363 - 2v_2}{9}

The mathematical expression for the conservation of kinetic energy is

\frac{1}{2}Mv^2+\frac{1}{2}mu^2 = \frac{1}{2}Mv_1^2+\frac{1}{2}mv_2^2

\frac{1}{2}(900)(47)^2+\frac{1}{2}(200)(-30)^2 = \frac{1}{2}(900)v_1^2+\frac{1}{2}(200)v_2^2    ................(ii)

$(9)(14)^2+(2)(-30)^2 = (9)v_1^2+2v_2^2$  

21681 = 9v_1^2+2v_2^2

Substituting (i) in (ii)

21681= 9\left( \frac{363-2v_2}{9}\right)^2+2v_2^2

(363-2v_2)^2+18v_2^2=195129

(363)^2+18v_2^2-2(363)(2v_2)+(363)^2-195129=0

22v_2^2-145v_2-63360=0

Solving the equation, we get

v_2=96 \ m/s, -30 \ m/s

The negative velocity is neglected.

Therefore, substituting 96 m/s for v_2 in (i), we get

v_1=\frac{363-(2 \times 96)}{9}

     = 19

Thus, only impulse of importance is used to find final velocity.

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