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Alja [10]
3 years ago
5

When the potential difference between the plates of a capacitor is increased by 3.50 V , the magnitude of the charge on each pla

te increases by 15.0 μC . What is the capacitance of this capacitor in μF?
Physics
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

42.9 μF

Explanation:

V = 3.50 V, Q = 150 μC

C = Q/V = 150/3.50 μF = 42.9 μF

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A food processor draws 8.47 A of current when connected to a potential difference of 110 V.
Andreyy89

Answer:

27.95[kW*min]

Explanation:

We must remember that the power can be determined by the product of the current by the voltage.

P=V*I

where:

P = power [W]

V = voltage [volt]

I = amperage [Amp]

Now replacing:

P=110*8.47\\P=931.7[W]

Now the energy consumed can be obtained mediate the multiplication of the power by the amount of time in operation, we must obtain an amount in Kw per hour [kW-min]

Energy = 931.7[kW]*30[days]*10[\frac{min}{1day} ]=279510[W*min]or 27.95[kW*min]

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Explanation:

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3 years ago
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Answer:

Notebook paper makes paper airplane fly farther

Explanation:

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4 0
2 years ago
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How much Gravitational Potential Energy does a 1.48 kg book at rest on top of a 2.4 m tall desk have?
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Gravitational Potential Energy GPE = mg∆h. 12. A 5.0 kg mass is initially sitting on the floor when it is lifted onto a table 1.15 meters high at.

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What is the student's kinetic energy at the bottom of the hill if he is moving
soldi70 [24.7K]

Answer:

KE = 10530 J or 10.53 KJ

Explanation:

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Let's apply the formula:

KE = 1/2 mv^2

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