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masya89 [10]
2 years ago
7

A printer has an original value of $7000. if it depreciates at the rate of 8 percent of the original cost per year, what is its

value at the end of 9 years?
Mathematics
1 answer:
Mrrafil [7]2 years ago
7 0

Based on the given parameters, the value of the printer after 9 years is $3304

<h3>How to determine the value in nine years?</h3>

The given parameters about the exponential function are

Initial value, a = $7000

Depreciation rate, r = 8%

Time, t = 9

Exponential functions are different from linear functions, and they are calculated using the following exponential function

A = a *(1 - r)^t

To calculate the value in nine years, we have:

Substitute the known values in the above equation

A = 7000 * (1 - 8%)^9

Express 8% as decimal

A = 7000 * (1 - 0.08)^9

Evaluate the difference

A = 7000 * (0.92)^9

Evaluate the exponent

A = 7000 * 0.472

Evaluate the product

A = 3304

Hence, the value of the printer after 9 years is $3304

Read more about exponential function at:

brainly.com/question/11464095

#SPJ1

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Answer:

 \frac{dy}{dt}  = 102

Step-by-step explanation:

<u>step(i)</u>

Given function y = 3 x³ - 2 x  ... (i)

Differentiating equation (i) with respective to 'x'

    \frac{dy}{dx} = 3 (3 x^{2} ) - 2(1)

Given x = -2

(\frac{dy}{dx} ) x_{=-2} = 3 (3 (-2)^{2} ) - 2(1)

(\frac{dy}{dx} ) x_{=-2} = 36 -2 =34

<u><em>Step(ii):-</em></u>

<u><em>we know that </em></u>

                     \frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

Given    \frac{dx}{dt} = 3  and \frac{dy}{dx} = 34

                  \frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

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Answer:

w = 7 cm

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(w + 12) = 0 or (w - 7) = 0

w = - 12 or w = 7

w cannot be negative

Hence, w = 7 cm

6 0
3 years ago
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