What is the sig fig of 0.00324?

A horizontal 745 N merry-go-round of radius

Arturiano [62]

Answer:

The kinetic energy of the merry-goround after 3.62 s is 544J

Explanation:

Given :

Weight w = 745 N

Radius r = 1.45 m

Force = 56.3 N

To Find:

The kinetic energy of the merry-go round after 3.62 = ?

Solution:

Step 1: Finding the Mass of merry-go-round

$m = \frac{ weight}{g}$

$m = \frac{745}{9.81 }$

m = 76.02 kg

Step 2: Finding the Moment of Inertia of solid cylinder

Moment of Inertia of solid cylinder I = $0.5 \times m \times r^2$

Substituting the values

Moment of Inertia of solid cylinder I

=> $0.5 \times 76.02 \times (1.45)^2$

=> $0.5 \times 76.02\times 2.1025$

=> $79.91 kg.m^2$

Step 3: Finding the Torque applied T

Torque applied T = $F \times r$

Substituting the values

T = $56.3 \times 1.45$

T = 81.635 N.m

Step 4: Finding the Angular acceleration

Angular acceleration , $\alpha = \frac{Torque}{Inertia}$

Substituting the values,

$\alpha = \frac{81.635}{79.91}$

$\alpha = 1.021 rad/s^2$

Step 4: Finding the Final angular velocity

Final angular velocity , $\omega = \alpha \times t$

Substituting the values,

$\omega = 1.021 \times 3.62$

$\omega = 3.69 rad/s$

Now KE (100% rotational) after 3.62s is:

KE = $0.5 \times I \times \omega^2$

KE = $0.5 \times 79.91 \times 3.69^2$

KE = 544J

6 0

3 years ago

Convert 252 cL into uL

OleMash [197]

Answer:

Explanation:

252,000

7 0

3 years ago

Which philosopher suggested that the mind and body are separate but that a link exists between them?

hammer [34]

<span>René Descartes suggests this.</span>

7 0

3 years ago

Read 2 more answers

As the shuttle bus comes to a sudden stop to avoid hitting a dog, it accelerates uniformly at -4.1 m/s2 as it slows from 9.0 m/s

Dennis_Churaev [7]

Answer:

The time interval of acceleration for the bus is 2.20 seconds

Explanation:

Acceleration is the rate of change of velocity

→ $a=\frac{v-u}{t}$

where a is the acceleration, v is the final velocity, u is the initial velocity

and t is the time

The given is:

The uniform acceleration = -4.1 m/s²

The bus slows from 9 m/s to 0 m/s

We need to find the time interval of acceleration for the bus

Lets use the rule above

→ a = -4.1 m/s² , v = 0 m/s , u = 9 m/s

→ $-4.1=\frac{0-9}{t}$

Multiply both sides by t

→ -4.1 t = -9

Divide both sides by -4.1

∴ t = 2.20 seconds

<em>The time interval of acceleration for the bus is 2.20 seconds</em>

3 0

3 years ago

You are given a box of 100 silver dollars, all facing heads up. You are instructed to shake the box 6 times; after each shake, y

densk [106]

50+25+12.5+6.25+ and on to 6 terms...

7 0

3 years ago

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