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Tatiana [17]
3 years ago
13

How many molecules are in 128g of H2O?

Chemistry
1 answer:
Lelechka [254]3 years ago
3 0

Answer:

4.28x10^24 molecules

Explanation:

From Avogadro's hypothesis, 1mole of any substance contains 6.02x10^23 molecules. From the above, we understood that 1mole of H2O also contains 6.02x10^23 molecules.

1mole of H2O = (2x1) + 16 = 2 + 16 = 18g

Now, if 18g of H2O contains 6.02x10^23 molecules,

Then 128g of H2O will contain = (128x 6.02x10^23) /18 = 4.28x10^24 molecules

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What is the formula of hexaaquamanganese(ii) sulfate? express your answer as a chemical formula?
Digiron [165]

Answer : The formula of hexaaquamanganese(II)sulfate is [Mn(H_2O)_6]SO_4.

Explanation :

Rules for writing formulas of coordination complexes :

  • Central metal is written first and then the ligands are written along with their prefixes.
  • The anion ligands are written before the neutral ligands.
  • If there are more than one anion ligands or neutral ligands then they are written in alphabetical order.

The given name of complex is, hexaaquamanganese(ii) sulfate.

In this, the central metal is manganese which is written as Mn and the ligand is water (which is a neutral ligand) is written as H_2O and an anion is sulfate which is written as SO_4.

Water is a neutral ligand and sulphate has a charge of -2. As the overall complex is neutral the metal bears a +2 charge which is represented in Roman numeral after the metal.

Therefore, the formula of hexaaquamanganese(II)sulfate is written as [Mn(H_2O)_6]SO_4.

3 0
3 years ago
What are the hazards, if any of the reactants AgNO3, and K2CrO4?
Mandarinka [93]
This is what i wrote in my notebook: (for AgNO3)
<span>Health Hazards Acute and Chronic:  ACUTE:
INHALATION - MAY CAUSE SEVERE IRRITATION TO MUCOUS MEMBRANES.
SKIN - MAY CAUSE SEVERE IRRITATION.
EYE - MAY CAUSE SEVERE IRRITATION.
CHRONIC: INHALATION, SKIN & INGESTION - MAY CAUSE ARSYRIA. Explanation of Carcinogenicity:THIS COMPOUND CONTAINS NO INGREDIENTS AT CONCENTRATIONS OF 0.1% OR GREATER THAT ARE CARCINOGENS OR SUSPECT CARCINOGENS.

</span><em><u>AgNO3 + K2CrO4 = Ag2CrO4 + KNO3</u></em>

3 0
3 years ago
Which of the following statements correctly describe the trends in ionic size?
8_murik_8 [283]

the spin quantum number has values+1212 of -1212 describes the trends in ionic size.

spin quantum is denoted by (s) as it represents the electronic configuration of the atom and the ionic size also depends on the electronic configuration of the sub-shells of the atom like l, m, n, s.

ionic size increases as the electronic configuration increases because the electron adds as we move up to a higher atomic number

all the other quantum numbers may vary from atom to atom but the spin quantum number remains either +1212 or -1212. it also describes the orientation of the electrons in an atom and the axis of electrons in an atom.

learn more about quantum number here;

brainly.com/question/2292596

#SPJ4

8 0
1 year ago
A scientist analyzes four samples of compounds. He finds the first compound contains 10 grams of sodium, 211 grams of potassium,
Zarrin [17]

Answer:

yea yea

Explanation:

6 0
3 years ago
A 3.50 amp power supply is used to deposit chromium from a solution of CrCl3. How long will it take to deposit 100.0 grams of ch
Norma-Jean [14]

Explanation:

The given data is as follows.

   Current (I) = 3.50 amp,        Mass deposited = 100.0 g

  Molar mass of Cr = 52 g

It is known that 1 faraday of electricity will deposit 1 mole of chromium. As 1 faraday means 96500 C and 1 mole of Cr means 52 g.

Therefore, 100 g of Cr will be deposited by "z" grams of electricity.

                z \times 52 g = 96500 \times 100 g

                         z = \frac{96500 \times 100 g}{52 g}

                            = 185576.9 C

As we know that, Q = I × t

Hence, putting the given values into the above equation as follows.

                      Q = I × t

           185576.9 C = 3.50 amp \times t  

                      t = 53021.9 sec

Thus, we can conclude that 100 g of Cr will be deposited in 53021.9 sec.

3 0
3 years ago
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