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Korvikt [17]
3 years ago
11

All of the following are categories for clutch covers except

Engineering
1 answer:
Lostsunrise [7]3 years ago
7 0

Whichever one is not one of these.

Molded disc. This type of disc produces less shock when the clutch engages. ...

Metal disc. Metal material is durable and therefore offers longer life cycle. ...

Single-plate type. This refers to clutches that use a single clutch disc between the flywheel and pressure plate. ...

Dual-plate type.

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Rank the magnitudes of the diffusion coefficients from greatest to least for the following systems:(a) Cr in Fe at 600°C; (b) C
jek_recluse [69]

Answer:

Explanation:

The rank of the magnitude of the diffusion coefficient from greatest to least is as follows:

C in Fe at 900°C > Cr in Fe at 900°C > Cr in Fe at 600°C

Reason

C in Fe is an interstitial impurity while Cr in Fe is a substutional impurity.Therefore interstitial impurity occurs in C in Fe systems,while substutitional diffusion occurs in Cr in Fe system.Interstitial is much faster than substitutional diffusion hence the order

Also with increasing temperature magnitude of diffusion coefficient increases,due to the relation.

     D = D₀exp(-Qd/RT)

Where D₀=Temperature independent per exponential

           Qd= The activation energy for diffusion

             R= Universal gas constant

              T=absolute temperature

3 0
3 years ago
Read 2 more answers
Is 4/8 bigger than 8/12 ?
Lostsunrise [7]

Is 4/8 bigger than 8/12 ? no

because 4/8 is 1/2 and 8/12 is more than a 1/2

5 0
3 years ago
Read 2 more answers
Which phrase best describes a safety-critical system?
MAVERICK [17]

Answer:

Life critical systems or computer systems that cause harm to people

4 0
3 years ago
The acceleration of a particle as it moves along a straight line is given
BARSIC [14]

Answer:

V_t=6 = 32 m/s

Explanation:

The origin is at point 0 with the positive motion to the right  

The instantaneous acceleration is change of velocity measured at infinitesimal interval of time, so the expression for instantaneous acceleration is:  

a=dv/dt

From here we can express dv as:

dv = a dt

Replace a by 2t — 1

dv = (2t — 1) dt

Integrate both sides of equation  

\int\limits^v_a  {2t-1} \, dv

v=t

a=t_0

putting these value in integral

<em>v-v_0=(t^2-t)-(t_0^2-t_0)</em>

We know that v_0 = 2 at t_0 = 0, so we'll replace t_0 and v_0 by their values

v — 2 = (t^2 — t) — (0^2 — 0)

From here we can write the expression for v as:  

v_t=6=6^2-6+2                             (1)  

So the velocity at t = 6 s is:

v_t=6 = 32 m/s

V_t=6 = 32 m/s

In order to determine the total distance travelled, we must check how maw times the particle has changed its direction, i.e. how many times its speed was equal to zero  

To do that, we'll just replace v by 0 in expression (1)

0 = t^2 — t + 2

The roots of the quadratic equation are:

t_1/2=1±  √(1^2-4*2*1)/2

Since 1^2-4*2*1 < 0, the quadratic equation have no real roots, so we can say that the velocity is always positive, i.e. to the right  

Now that we have all the details, we can correctly draw the path of the particle  

We can see from the sketch that the total distance traveled is:  

s^T=Δs_0-1

s^T=| s_1 - s_0 |

Replace s_0 by its value  

s^T=| s_1 - 1 |                                        (2)  

In order to determine the position of particle at t = 6 s, we'll need to determine the expression for s as function of time  

Since we have already wrote expression for v as function of time (step 2), we'll use expression  to get the expression for s

v= ds/dt  

Multiply both sides of equation by dt

v dt = ds

Replace v by expression (1)

(t^2 — t + 2) dt = ds

Integrate both sides of equation  

\int\limits^t_b {x} \, dx

t=s

b=(s=0)

x=(t^2 — t + 2)

dx=ds

putting these value in integral

(t^3/3-t^2/2+t)-(t_0^3/3-t_0^2/2+t_0)= s-s_0

Since s = 1 m at t = 0, and we want to determine the position s at t = 6, we'll replace so by 1, t_0 by 0 and t by 6  

(6^3/3-6^2/2+6)-(0^3/3-0^2/2+0)=s_t=6-1

4 0
3 years ago
What is the total kinetic energy of a 2500 lbm car when it is moving at 80 mph (in BTU)?
Damm [24]

Answer:

The kinetic energy will be 687.186 BTU

Explanation:

We have given mass of car = 2500 lbm

We know that 1 lbm = 0.4535 kg

So 2500 lbm = 2500\times 0.4535=1133.75kg

Speed = 80 mph

We know that 1 mile = 1609.34 meter

1 hour = 3600 sec

So 80mph=\frac{80\times 1609.34}{3600}=35.763m/sec

We know that kinetic energy E=\frac{1}{2}mv^2=\frac{1}{2}\times 1133.75\times 35.76^2=725.033KJ

We know that 1 KJ = 0.9478 BTU

So 725.033 KJ = 725.033×0.9478 = 687.186 BTU

3 0
3 years ago
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