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victus00 [196]
2 years ago
12

What is the frequency in hertz of a signal that repeats 80,000 times within one minute? What is its period?

Physics
1 answer:
Harman [31]2 years ago
5 0

1333.3 is the frequency in the hertz of a signal that repeats 80,000 times within one minute. 0.00075 is its period.

The frequency of a repeated event is its number of instances per unit of time. In some cases, it is also referred to as temporal frequency or ordinary frequency to underline differences with spatial and angular frequencies, respectively.

The length of time it takes for a particle in a medium to complete one full vibrational cycle is the period of a wave. Being a time, a period is measured in time units like seconds, hours, days, or years. The Earth's orbit around the Sun has a duration of around 365 days, and one cycle of the Earth lasts 365 days.

frequency = cycle /second

frequency = 80000 / 60

frequency = 1333.3 hertz

Period = 1 / frequency

Period = 1 / 1,333.3

Period = 0.00075

To know more about  frequency refer to:  brainly.com/question/14472937

#SPJ4

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Sometimes you are able to hear your echo in rooms due to the acoustics of the structure. If you call
malfutka [58]

Answer: Plz mark me brainliest i am 12 and i've never been marked brainliest.

Explanation:

Sound will echo in an empty room because if there is nothing to stop the sound from reflecting between hard surfaces, such as the walls, windows, ceiling, and floor . Since each surface is not a perfect reflector, some of the sound energy will be absorbed by the surface.

8 0
3 years ago
b. Ron bicycles forward with an acceleration of 2.1 m/s2. If he is applying a forward force of 195 N, what is his mass?
cricket20 [7]

Answer:

<h2>92.86 kg </h2>

Explanation:

lThe mass of an object given only it's force and acceleration can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question

f = 195 N

a = 2.1 m/s

We have

m =  \frac{195}{2.1 }  = 92.857142... \\

We have the final answer as

<h3>92.86 kg</h3>

Hope this helps you

8 0
2 years ago
Consider a spherical volume of space that is large enough to be considered homogeneous. Also consider a particle on the surface
LenKa [72]

Answer:

Option A applies.

A.  Greater than its escape speed from the mass within the volume

Explanation:

Here it is mentioned that the spherical volume is large enough for the space to be considered as homogeneous. Also, the pressure within the volume is negligible, so that will not result into the re collapse of the Universe. Now as per our knowing, Hubble's Law relates the average speed of the particle to the distance R between the Earth and the particle. So, if the particle's speed is greater than it's escape speed from the mass within the volume, then the Universe is bound to re collapse back again. Option A applies.

3 0
3 years ago
How much charge does a 9.0 v battery transfer from the negative to the positive terminal while doing 39 j of work?
sdas [7]
The work done by the battery is equal to the charge transferred during the process times the potential difference between the two terminals of the battery:
W=q \Delta V
where q is the charge and \Delta V is the potential difference.

In our problem, the work done is W=39 J while the potential difference of the battery is \Delta V = 9.0 V, so we can find the charge transferred by the battery:
q= \frac{W}{\Delta V}= \frac{39 J}{9.0 V}=4.33 C
3 0
3 years ago
An engine absorbs 1749 J from a hot reservoir and expels 539 J to a cold reservoir in each cycle. a. What is the engine’s effici
Masja [62]

Answer:

a)η = 69.18 %

b)W= 1210 J

c)P=3967.21 W

Explanation:

Given that

Q₁ = 1749 J

Q₂ = 539  J

From first law of thermodynamics

Q₁   = Q₂ +W

W=Work out put

Q₂=Heat rejected to the cold reservoir

Q₁ =heat absorb by hot  reservoir

W= Q₁- Q₂

W= 1210 J

The efficiency given as

\eta=\dfrac{W}{Q_1}

\eta=\dfrac{1210}{1749}

\eta=0.6918

η = 69.18 %

We know that rate of work done is known as power

P=\dfrac{W}{t}

P=\dfrac{1210}{0.305}\ W

P=3967.21 W

8 0
3 years ago
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