The image produced is magnified and real.
Answer:
7.72 Liters
Explanation:
normal body temperature = T_body =37° C
temperature of ice water = T_ice =0°c
specfic heat of water = c_{water} =4186J/kg.°C
if the person drink 1 liter of cold water mass of water is = m = 1.0kg
heat lost by body is Qwater =mc_{water} ΔT
= mc{water} ( T_ice - T_body)
= 1.0×4186× (0 -37)
= -154.882 ×10^3 J
here negative sign indicates the energy lost by body in metabolic process energy expended due to brisk - hour long walk is Q_{walk} = 286 kilocalories
= 286×4186J
so number of liters of ice water have to drink is
n×Q_{water} =Q_{walk} n= Q_{walk}/ Q_{water}
= 286×4186J/154.882×10^3 J
= 7.72 Liters
Metallic bonding<span> is the force of attraction between valence electrons and the metal ions. It is the sharing of many detached electrons between many positive ions,
Hopefully this can help you understand
</span>
The distance travelled is 10 m and the velocity gained at the end of this time is 2 m/s.
<h3>Velocity of the object at the end of the time</h3>
F = mv/t
where;
- m is mass of the object
- v is velocity of the object
- t is time
Ft = mv
v = Ft/m
v = (50 x 10)/250
v = 2 m/s
<h3>Distance traveled by the object</h3>
v² = u² + 2as
where;
u is initial velocity = 0
a is acceleration
a = F/m
a = 50 N/ 250 kg
a = 0.2 m/s²
v² = 0 + 2as
s = v²/2a
s = (2²)/(2 x 0.2)
s = 10 m
Thus, the distance travelled is 10 m and the velocity gained at the end of this time is 2 m/s.
Learn more about distance here: brainly.com/question/2854969
#SPJ1
