1. In 1687 following 18 months of intense and effectively nonstop work
2.Hooke
3.Halley
4. Halley urged newton to write Principia mathematica and when the Royal society declined to pay the cost of publishing Halley paid for it out of his own pocket
5.Through using a telescope Galileo Galilei was able to prove the theories of sciences Isaac newton
6. He believe that the speed of an object motion is proportional to the force being applied and inversely proportional to the density of the medium he reason that the object moving in a void would move in definitely fast and thus any and all objects
7. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force
8.gottfried wilhelm von leibniz
Answer:
0.425M NaOH assuming the volume of KHP was 25.50mL and the volume of the NaOH solution was 30.0mL
Explanation:
The KHP reacts with NaOH as follows:
KHP + NaOH → KNaP + H₂O
<em>Where 1 mole of KHP reacts per mole of KNaP</em>
<em />
That means, the moles of KHP added to the NaOH solution = Moles NaOH at equivalence point. With the moles of NaOH and the volume in liters we can find the molar concentration of NaOH.
<em>Assuming the volume added of KHP was 25.50mL and the solution of NaOH contains 30.0mL (0.0300L), the concentration of the NaOH is:</em>
<em />
<em>Moles KHP = Moles NaOH:</em>
25.50mL = 0.02550L * (0.500mol / L) = 0.01275 moles KHP = Moles NaOH
<em>Molarity NaOH:</em>
0.01275 moles NaOH / 0.0300L =
<h3>0.425M NaOH assuming the volume of KHP was 25.50mL and the volume of the NaOH solution was 30.0mL</h3>
a. We first calculate the moles of sucrose needed
moles sucrose = 0.250 M * 0.25 L
moles sucrose = 0.0625 mol
The molar mass of sucrose 342.3 g/mol, so the mass of
sucrose needed is:
mass sucrose = 0.0625 mol * 342.3 g/mol
mass sucrose = 21.4 grams
So simply dissolved about 21.4 grams of sucrose in 250 mL
solution.
b. We use the formula:
M1 V1 = M2 V2
1.50 M * V1 = 0.100 M * 0.350 L
V1 = 0.0233 L = 23.3 mL
So simply take 23.3 mL of solution from 1.50 M then dilute
it with water until 350 mL to make 0.100 M.
For the compound B the following statement is correct-
B. It is an ether because it is unable to form a hydrogen bond, so it is less soluble in water.
The solubility of alcohol in water depends upon the capability of formation of hydrogen bond in the solute. Now in alcohol the -OH group is polar in nature which enhance the possibility of hydrogen bond formation and it is more soluble in water.
On the other hand although there presence a -O- functional group in ether. It is less soluble in water due to non polarity of the functional group.
From the given data it is seen that compound A is more soluble in water than compound B. Thus it may be predicted that compound A is alcohol and B is ether.
Henceforth, for the compound B the following statement is correct-
B. It is an ether because it is unable to form a hydrogen bond, so it is less soluble in water.
The reason of incorrect options:
A. compound B cannot be an alcohol as it is less soluble in water.
C. In ether the functional group is -O-, thus electronegative atom (O) is present.
D. As both the compound (alcohol and ether) has equal molecular mass thus the organic chain will be same in alcohol and the hydrogen bond interaction will be more prominent than the dispersion force between the -OH group.
