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Alik [6]
3 years ago
10

What does the law of conservation of mass state?

Chemistry
2 answers:
katrin [286]3 years ago
8 0

Answer:

matter cannot be created nor destroyed

Explanation:

natulia [17]3 years ago
7 0

Answer:

Mass cannot be created nor destroyed in a chemical reaction

Explanation:

The law of conservation of mass was stated by Antoine lavoisier in 18th century which states that for a isolated system the mass can neither be created nor be destroyed in a chemical reaction. It means that the total mass of the reactants is equal to the total mass of the product formed i.e there is no change in the mass of the reactants even after the reaction which is stated by the law of the conservation of the mass.

The mass of the elements are not created or destroyed but their form is changed to another form of atoms or molecules with conserved mass.  

For a balanced chemical equation of the formation of the water, 4 grams of hydrogen combines with 32 grams of the oxygen to give 36 grams of the water where the sum of the mass of the reactant is equals to the mass of the product.

You might be interested in
Which three temperature readings all mean the same thing?
allochka39001 [22]

Answer: The correct answer is D. 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit.

Explanation:

Conversion of degree Celsius to Kelvin :

K=^oC+273

Conversion of degree Celsius to degrees Fahrenheit :

^oF=(\frac{9}{5}\times ^oC)+32

By using these two conversion factors, we get the three temperature readings all mean the same thing.

For option A :

K=^oC+273=100+273=373K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF

For option B :

K=^oC+273=100+273=373K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF

For option C :

K=^oC+273=0+273=273K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF

For option D :

K=^oC+273=0+273=273K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF

From the given options, only option (D) is correct.

Hence, the correct option is, (D) 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit

Hope this helps!

8 0
3 years ago
Read 2 more answers
Please help!!!<br> Its not chemistry is science.
laiz [17]
You would want to know everything just Incase anything happens because maybe you get lost
7 0
4 years ago
Which of the following measurements has three significant figures?
Free_Kalibri [48]

The correct answer is <u>C: 0.510 m</u>

<u></u>

N I C E - D A Y!

8 0
3 years ago
Read 2 more answers
So guess what I did!!
Lapatulllka [165]

Answer:

what

Explanation:

what did u do

7 0
3 years ago
A. Based on the activation energies and frequency factors, rank the following reactions from fastest to slowest reaction rate, a
deff fn [24]

Answer:

A) E_{a} = 350KJ/mol, E_{a} = 50KJ/mol, E_{a} = 50KJ/mol

     A = 1.5×10^{-7}s^{-1}, A = 1.9×10^{-7} s^{-1}, A=1.5×10^{-7} s^{-1}

B) 4.469

Explanation:

From Arrhenius equation

      K=Ae^{\frac{E_{a} }{RT} }

where; K = Rate of constant

            A = Pre exponetial factor

            E_{a} = Activation Energy

             R = Universal constant

             T = Temperature in Kelvin

Given parameters:

E_{a} =165KJ/mol

T_{1}=505K

T_{2}=525K

R=8.314JK^{-1}mol^{-1}

taking logarithm on both sides of the equation we have;

InK=InA-\frac{E_{a} }{RT}

since we have the rate of two different temperature the equation can be derived as:

In(\frac{K_{2} }{K_{1} } )=\frac{E_{a} }{R}(\frac{1}{T_{1} } -\frac{1}{T_{2} } )

In(\frac{K_{2} }{K_{1} } )=\frac{165000J/mol}{8.314JK^{-1}mol^{-1}  }.(\frac{1}{505} -\frac{1}{525} )

In(\frac{K_{2} }{K_{1} } )= 19846.04×7.544×10^{-5} = 1.497

\frac{K_{2} }{K_{1} } =e^{1.497} = 4.469

 

6 0
3 years ago
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